使用数组存储多个用户生成的整数

Question

Description of Example

我是 Java 新手，我正在尝试弄清楚如何执行此示例。我最初计划将 3 个用户猜测存储到一个名为 UserGuess 的数组中，并将 3 个尝试猜测存储在另一个数组中，但我对如何将 USER 输入存储到一个数组中感到困惑（我一直在使用固定数字） .我也很困惑，如果 UserGuess 数组的整数等于尝试猜测的整数，我将如何写出，会出现一个消息框，指示锁已打开或尝试猜测错误。

package ComboLockerDrive;

导入 javax.swing.JOptionPane;

公共类 ComboLockerDrive {

public static void main(String[] args) {




    int digit1 = Integer.parseInt(JOptionPane.showInputDialog("Enter the first digit of your locker combo: "));
    int digit2 = Integer.parseInt(JOptionPane.showInputDialog("Enter the second digit of your locker combo: "));
    int digit3 = Integer.parseInt(JOptionPane.showInputDialog("Enter the third digit of your locker combo: "));
    System.out.println("The code has been set!");

     int[] combination = new int[3];
     combination[0] = digit1;
     combination[1] = digit2;
     combination[2] = digit3;

     System.out.println("Now we will try and open the lock!");

     int[] attemptedGuess = new int[3];

     int Guess1 = Integer.parseInt(JOptionPane.showInputDialog("Enter your first guess: "));
     int Guess2 = Integer.parseInt(JOptionPane.showInputDialog("Enter your second guess: "));
     int Guess3 = Integer.parseInt(JOptionPane.showInputDialog("Enter your third guess: "));

     attemptedGuess[0] = Guess1;
     attemptedGuess[1] = Guess2;
     attemptedGuess[2] = Guess3;

     if(combination == attemptedGuess) {
         System.out.println("The lock opened, congratulations, you got the combination right!");
     } 

     else {
         System.out.println("The lock does not open, the combination you tried was incorrect");
     }


}

}

这是我到目前为止所拥有的，没有任何错误，但是当我输入正确的组合时，它说组合不正确。这是否意味着我没有正确填写数组？

Answer 1

你不能仅仅为了相等而匹配两个数组，因为当你做combination == attemptedGuess 你试图匹配总是不同的引用时。相反，您应该匹配索引处的各个元素。

你基本上可以匹配所有数字，如果其中一个不匹配，你可以说组合不正确，否则它是正确的。

类似这样的： 替换代码

if(combination == attemptedGuess) {
     System.out.println("The lock opened, congratulations, you got the combination right!");
 } 
 else {
     System.out.println("The lock does not open, the combination you tried was incorrect");
 }

有了这个

        for(int i=0;i<3;i++){
            if(attemptedGuess[i]!=combination[i]){
                System.out.println("The lock does not open, the combination you tried was incorrect");
                return;
            }
        }
        System.out.println("The lock opened, congratulations, you got the combination right!");

或者只是按照@sam的建议

if(Arrays.equals(attemptedGuess, combination)){
    System.out.println("The lock opened, congratulations, you got the combination right!");
}else{
    System.out.println("The lock does not open, the combination you tried was incorrect");
}