休眠在错误的表中寻找列

Question

我有这个查询可以在原生 SQL 和 Java 中的 Hibernate 中使用。

错误提示

无法解析属性：entityName ...

（或数量）当我使用 pageable 对这两列之一的结果进行排序时。

Hibernate 也无法将项目映射到 Page<McConsumerBalanceEntity> 并返回 pageimpl 的对象，所以我使用 List<Object[]> 手动映射项目，这是可行的。

休眠版本是 5.3.7。数据库是 PostgreSQL 10.5。 Spring Boot 是 2.1.0

@Query(
        value = "select csr.id, csr.firstName, csr.lastName, " +
                "sum (case " +
                    "when acs.type = 'PAYMENT' then acs.amount " +
                    "else -acs.amount " +
                "end) as amount, " +
                "me.id as entityId, " +
                "me.name as entityName " +
                "from McConsumerEntity csr, EbAccountConsumerEntity acs, McEntity me " +
                "where csr.idMcEntity in :childEntityIds " +
                "and csr.idMcEntity = me.id " +
                "and csr.id = acs.idMcConsumer " +
                "and amount > 0 " +
                "group by csr.id, me.id, me.name ")

public class McConsumerBalanceEntityGenerated implements Serializable {

    private static final long serialVersionUID = 217L;

    @Id
    @GeneratedValue(generator = "sequence_null", strategy = GenerationType.SEQUENCE)
    @SequenceGenerator(name = "sequence_null",
            sequenceName = "sequence_null", allocationSize = 100)
    protected Long id;



    @Column(name = "amount")
    protected BigDecimal amount;


    @Column(name = "entity_id")
    protected Long entityId;


    @Column(name = "entity_name")
    protected String entityName;


    @Column(name = "first_name")
    protected String firstName;


    @Column(name = "last_name")
    protected String lastName;




    //---------------------------------------------------------------------
    public McConsumerBalanceEntityGenerated() {
        super();
    }

/*
    //---------------------------------------------------------------------
    private McConsumerBalanceEntity(Builder builder) {
        this.id = builder.id;
    }
*/

    //---------------------------------------------------------------------
    public Long getId() {
        return id;
    }

    

    /**
     * Access method for the amount property.
     *
     * @return the current value of the amount property
     */
    public BigDecimal getAmount() {
        return this.amount;
    }



    /**
     * Sets the value of the amount property.
     *
     * @param aAmount the new value of the version property
     */
    public void setAmount(BigDecimal aAmount) {
        this.amount = aAmount;
    }


    /**
     * Access method for the entityId property.
     *
     * @return the current value of the entityId property
     */
    public Long getEntityId() {
        return this.entityId;
    }



    /**
     * Sets the value of the entityId property.
     *
     * @param aEntityId the new value of the version property
     */
    public void setEntityId(Long aEntityId) {
        this.entityId = aEntityId;
    }


    /**
     * Access method for the entityName property.
     *
     * @return the current value of the entityName property
     */
    public String getEntityName() {
        return this.entityName;
    }



    /**
     * Sets the value of the entityName property.
     *
     * @param aEntityName the new value of the version property
     */
    public void setEntityName(String aEntityName) {
        this.entityName = aEntityName;
    }


    /**
     * Access method for the firstName property.
     *
     * @return the current value of the firstName property
     */
    public String getFirstName() {
        return this.firstName;
    }



    /**
     * Sets the value of the firstName property.
     *
     * @param aFirstName the new value of the version property
     */
    public void setFirstName(String aFirstName) {
        this.firstName = aFirstName;
    }


    /**
     * Access method for the lastName property.
     *
     * @return the current value of the lastName property
     */
    public String getLastName() {
        return this.lastName;
    }



    /**
     * Sets the value of the lastName property.
     *
     * @param aLastName the new value of the version property
     */
    public void setLastName(String aLastName) {
        this.lastName = aLastName;
    }



/*    //---------------------------------------------------------------------
    public static class Builder {

        private Long id;

        public Builder setId(Long id) {
            this.id = id;
            return this;
        }

        public McConsumerBalanceEntity build() {
            return new McConsumerBalanceEntity(this);
        }
    }*/

}

Answer 1

由于错误明确指出无法解析属性：entityName，这意味着该列在它尝试获取的实体中不存在。我可以观察到，在您的 SQL 本机查询中，您正试图从 me.Name 获取它，并且根据您提供的实体，它存在于 McConsumerBalanceEntityGenerated 中。所以尝试加入这个实体并从这个表/实体中获取实体名称。

Answer 2

您并没有说您正在使用哪个 Hibernate 版本或什么数据库，所以这里的每个人都必须猜测这些问题以及更多问题。如果您想获得好的答案，请考虑在您的问题中提供更多详细信息或聘请顾问为您完成工作。您在这里提问的方式就像是在问机械师“我的福特汽车在快速行驶时发出奇怪的声音，这是什么问题？”。

话虽如此，我将假设您使用 Oracle 开始猜测。也许您遇到了类似以下的问题：https://discourse.hibernate.org/t/issues-in-migrating-from-hibernate-5-3-3-to-5-3-4/5679/2

Hibernate 也无法将项目映射到 Page 并返回对象的 pageimpl，因此我正在使用 List

这是意料之中的。 Hibernate 不做“推理”或类似的事情。如果要返回 McConsumerBalanceEntity，请使用 JPQL 构造函数表达式。