使用 HQL/Criteria Java 的分层数据答案

【问题标题】：hierarchical data using HQL/Criteria Java使用 HQL/Criteria Java 的分层数据
【发布时间】：2020-08-15 20:07:14
【问题描述】：

我有桌子：

+----+-------------------+------+-------------------+-------+
| id | exType            | exId | depType           | depId |
+----+-------------------+------+-------------------+-------+
| 1  | Ceo               | 1    | Board Of Director | 1     |
| 2  | Board Of Director | 1    | Manager           | 4     |
| 3  | Board Of Director | 1    | Manager           | 5     |
| 4  | Manager           | 4    | TeamLead          | 1     |
| 5  | Manager           | 5    | TeamLead          | 2     |
| 6  | TeamLead          | 1    | Member            | 7     |
| 7  | TeamLead          | 1    | Member            | 8     |
| 8  | TeamLead          | 1    | Member            | 9     |
| 9  | TeamLead          | 1    | Member            | 10    |
| 10 | TeamLead          | 2    | Member            | 19    |
+----+-------------------+------+-------------------+-------+

我想要所有成员的，当我以exType 作为经理和exId 作为4 我想要：
```
Member  7
Member  8
Member  9   
Member  10
```
或者我想要所有成员的，当我以exType 作为TeamLead 和exId 作为1 我想要：
```
Member  7
Member  8
Member  9
Member  10
```

【问题讨论】：

标签： jpa hql criteria criteria-api

【解决方案1】：

Select depType, depId from table where exType in (Select depType from table where exType='Manager') a and exId in (Select depId from table where exId='4')

Select depType, depId from table where exType = 'TeamLead' and exId = '1'

【讨论】：

这里我只得到一个级别，不完全或者请你在上面详细说明