具有多个集合的 JPA 实体结果集重复

Question

Contact 实体定义了与两个 MySQL 表中存在的电子邮件和昵称类型的两个实体集合的关系。

我的问题是返回的结果集包含重复的电子邮件和昵称。

{
  "contactId": 1,
  "givenName": "toast",
  "middleName": "brown",
  "familyName": "jam",
  "dob": "2014-11-19",
  "contactEmailAddress": [
    {
      "emailAddressId": 1,
      "emailAddress": "donald.duck@disney.com",
      "contactId": 1
    },
    {
      "emailAddressId": 1,
      "emailAddress": "donald.duck@disney.com",
      "contactId": 1
    },
    {
      "emailAddressId": 2,
      "emailAddress": "mickey.mouse@disney.com",
      "contactId": 1
    },
    {
      "emailAddressId": 2,
      "emailAddress": "mickey.mouse@disney.com",
      "contactId": 1
    }
  ],
  "contactNickname": [
    {
      "contactNicknameId": 1,
      "nickname": "mm",
      "contactId": 1
    },
    {
      "contactNicknameId": 2,
      "nickname": "mouse",
      "contactId": 1
    },
    {
      "contactNicknameId": 1,
      "nickname": "mm",
      "contactId": 1
    },
    {
      "contactNicknameId": 2,
      "nickname": "mouse",
      "contactId": 1
    }
  ]
}

如果我从 Contact 实体中删除 ContactNickname 集合，结果集如下。

{
  "contactId": 1,
  "givenName": "toast",
  "middleName": "brown",
  "familyName": "jam",
  "dob": "2014-11-19",
  "contactEmailAddress": [
    {
      "emailAddressId": 1,
      "emailAddress": "donald.duck@disney.com",
      "contactId": 1
    },
    {
      "emailAddressId": 2,
      "emailAddress": "mickey.mouse@disney.com",
      "contactId": 1
    }
  ]
}

我希望有一组不同的电子邮件地址和一组不同的昵称，但事实并非如此。我在做什么不正确。

使用 JPA，我将类映射如下。

@Entity
@Table(name="contact")
public class Contact implements Serializable {    
    @OneToMany(fetch=FetchType.EAGER)
    @JoinColumn(name="contact_id")
    private Collection<ContactEmailAddress> contactEmailAddress;

    @OneToMany(fetch=FetchType.EAGER)
    @JoinColumn(name="contact_id")
    private Collection<ContactNickname> contactNickname;

    public Collection<ContactEmailAddress> getContactEmailAddress(){
        return this.contactEmailAddress;
    }

    public void setContactEmailAddress(Collection<ContactEmailAddress> contactEmailAddress){        
        this.contactEmailAddress=contactEmailAddress;
    }

    public Collection<ContactNickname> getContactNickname(){
        return this.contactNickname;
    }

    public void setContactNickname(final Collection<ContactNickname> contactNickname){
        this.contactNickname=contactNickname;
    }    
}

@Entity
@Table(name="contact_email_address")
public class ContactEmailAddress implements Serializable {   
    @Id
    @GeneratedValue
    @Column(name="email_address_id")
    private int emailAddressId;

    @Column(name="email_address")
    private String emailAddress;

    @Column(name="contact_id")
    private int contactId;

  public void setContactId(int contactId){
        this.contactId=contactId;
    }

    public int getContactId(){
        return this.contactId;
    }.

   public int getEmailAddressId(){
        return emailAddressId;
    }

    public void setEmailAddressId(final int emailAddressId){
        this.emailAddressId=emailAddressId;
    }

    public String getEmailAddress(){
        return emailAddress;
    }

    public void setEmailAddress(String emailAddress){
        this.emailAddress=emailAddress;
    }
}

@Entity
@Table(name="contact_nickname")
public class ContactNickname implements Serializable {
    @Id
    @GeneratedValue
    @Column(name="contact_nickname_id")
    private int contactNicknameId;

    @Column(name="nickname")
    private String nickname;

    @Column(name="contact_id")
    private int contactId; 

    public int getContactNicknameId(){
        return contactNicknameId;
    }

    public void setContactNicknameId(final int contactNicknameId){
        this.contactNicknameId=contactNicknameId;
    }

    public String getNickname(){
        return this.nickname;
    }

    public void setNickname(String nickname){
        this.nickname=nickname;
    }    

    public void setContactId(int contactId){
        this.contactId=contactId;
    }

    public int getContactId(){
        return this.contactId;
    }
}

当复制发生时，Hibernate 正在运行以下内容。

SELECT contact0_.contact_id             AS contact_1_0_0_, 
       contact0_.dob                    AS dob2_0_0_, 
       contact0_.family_name            AS family_n3_0_0_, 
       contact0_.given_name             AS given_na4_0_0_, 
       contact0_.middle_name            AS middle_n5_0_0_, 
       contactema1_.contact_id          AS contact_2_0_1_, 
       contactema1_.email_address_id    AS email_ad1_1_1_, 
       contactema1_.email_address_id    AS email_ad1_1_2_, 
       contactema1_.contact_id          AS contact_2_1_2_, 
       contactema1_.email_address       AS email_ad3_1_2_, 
       contactnic2_.contact_id          AS contact_2_0_3_, 
       contactnic2_.contact_nickname_id AS contact_1_3_3_, 
       contactnic2_.contact_nickname_id AS contact_1_3_4_, 
       contactnic2_.contact_id          AS contact_2_3_4_, 
       contactnic2_.nickname            AS nickname3_3_4_ 
FROM   contact contact0_ 
       LEFT OUTER JOIN contact_email_address contactema1_ 
                    ON contact0_.contact_id = contactema1_.contact_id 
       LEFT OUTER JOIN contact_nickname contactnic2_ 
                    ON contact0_.contact_id = contactnic2_.contact_id 
WHERE  contact0_.contact_id =? 

亲切的问候， 伊恩。

Answer 1

如果您不想在集合中出现重复项，则应在实体中使用 Set 而不是 Collection。