【问题标题】:I'd like to serialize an xml file into java objects我想将 xml 文件序列化为 java 对象
【发布时间】:2011-03-26 09:21:56
【问题描述】:

我有这个 xml 文件,我想在一个 java 对象中取消它。我正在使用 MOXy JAXB 库。

test.xml

    <?xml version="1.0" encoding="UTF-8"?>

<project >
    <type>org.netbeans.modules.ant.freeform</type>
            <compilation-unit>
                <package-root>src</package-root>
                <classpath mode="boot">${sunspot.bootclasspath}</classpath>
                <classpath mode="compile">${sunspot.classpath}</classpath>
                <built-to>build</built-to>
                <source-level>1.4</source-level>
            </compilation-unit>

</project>

这是我的 java 类: Project.java

package example;

import java.util.List;

import javax.xml.bind.annotation.*;


import org.eclipse.persistence.oxm.annotations.XmlPath;

@XmlRootElement
@XmlType(name = "project",propOrder = {"type", "compilation_unit"})
public class Project {
    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    private String type;


    @XmlPath("/compilation-unit")
    @XmlElement(name = "compilation-unit")
    private CompilationUnit compilation_unit;

    public CompilationUnit getPckg() {
        return compilation_unit;
    }

    public void setPckg(String pckg) {
        this.compilation_unit = compilation_unit;
    }


}

编译单元

package example;

import org.eclipse.persistence.oxm.annotations.XmlPath;

import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import java.util.List;

/**
 * Created by IntelliJ IDEA.
 * User: ronny
 * Date: Aug 5, 2010
 * Time: 11:28:37 AM
 * To change this template use File | Settings | File Templates.
 */
@XmlType(name = "compilation-unit", propOrder = {"package_root","built_to" ,"source_level" ,"classpath"})

public class CompilationUnit {
    public String getPackage_root() {
        return package_root;
    }

    public void setPackage_root(String package_root) {
        this.package_root = package_root;
    }

    public String getBuilt_to() {
        return built_to;
    }

    public void setBuilt_to(String built_to) {
        this.built_to = built_to;
    }

    public String getSource_level() {
        return source_level;
    }

    public void setSource_level(String source_level) {
        this.source_level = source_level;
    }

    public List<Classpath> getClasspath() {
        return classpath;
    }

    public void setClasspath(List<Classpath> classpath) {
        this.classpath = classpath;
    }

    private String package_root;
    private String built_to;
    private String source_level;
    private List<Classpath> classpath;

}

类路径:

package example;

import javax.xml.bind.annotation.XmlAttribute;

/**
 * Created by IntelliJ IDEA.
 * User: leontiad
 * Date: Aug 5, 2010
 * Time: 11:33:52 AM
 * To change this template use File | Settings | File Templates.
 */
public class Classpath {
    @XmlAttribute
    private String mode;
}

以及用于测试的 Demo 类:

package example;

import java.io.FileInputStream;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Project.class);

        FileInputStream xml = new FileInputStream("C:\\task.xml");
        Project project = (Project) jc.createUnmarshaller().unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(project, System.out);
    }
}

我得到的输出如下:

<?xml version="1.0" encoding="UTF-8"?>
<project>
   <type>org.netbeans.modules.ant.freeform</type>
</project>

谁能帮助理解为什么没有打印整个 xml 文件而只打印其中的一部分?

【问题讨论】:

    标签: xml jaxb eclipselink moxy


    【解决方案1】:

    我没有使用太多 JAXB,但我认为compile_unit 字段不需要@XmlPath("/compilation-unit")。我认为当xml反序列化时,路径注释与xml不匹配。

    【讨论】:

    • 是的,问题是@XmlPath 注释。另外我必须在CompilationUnit.java 的每个变量中添加@XmlElement 注释但是 有问题: 它只打印属性。我想看看它应该包含在 Classpath.java 文件中以保存元素的值..?
    • 有关@XmlPath 注释的更多信息,请参见:bdoughan.blogspot.com/2010/07/xpath-based-mapping.html
    【解决方案2】:

    您只是遗漏了几个注释,以下是更正后的类:

    编译单元

    import javax.xml.bind.annotation.XmlElement;
    import javax.xml.bind.annotation.XmlType; 
    import javax.xml.bind.annotation.XmlAccessType; 
    import javax.xml.bind.annotation.XmlAccessorType; 
    import java.util.List; 
    
    /** 
     * Created by IntelliJ IDEA. 
     * User: leontiad 
     * Date: Aug 5, 2010 
     * Time: 11:28:37 AM 
     * To change this template use File | Settings | File Templates. 
     */ 
    @XmlType(name = "compilation-unit", propOrder = {"package_root","built_to" ,"source_level" ,"classpath"}) 
    @XmlAccessorType(XmlAccessType.FIELD)
    public class CompilationUnit { 
        public String getPackage_root() { 
            return package_root; 
        } 
    
        public void setPackage_root(String package_root) { 
            this.package_root = package_root; 
        } 
    
        public String getBuilt_to() { 
            return built_to; 
        } 
    
        public void setBuilt_to(String built_to) { 
            this.built_to = built_to; 
        } 
    
        public String getSource_level() { 
            return source_level; 
        } 
    
        public void setSource_level(String source_level) { 
            this.source_level = source_level; 
        } 
    
        public List<Classpath> getClasspath() { 
            return classpath; 
        } 
    
        public void setClasspath(List<Classpath> classpath) { 
            this.classpath = classpath; 
        } 
    
        @XmlElement(name="package-root") 
        private String package_root;
    
        @XmlElement(name="built-to")
        private String built_to; 
    
        @XmlElement(name="source-level")
        private String source_level; 
        private List<Classpath> classpath; 
    
    }
    

    项目

    import javax.xml.bind.annotation.XmlAccessType;
    import javax.xml.bind.annotation.XmlAccessorType;
    import javax.xml.bind.annotation.XmlElement;
    import javax.xml.bind.annotation.XmlRootElement;
    import javax.xml.bind.annotation.XmlType;
    
    @XmlRootElement 
    @XmlType(name = "project",propOrder = {"type", "compilation_unit"}) 
    @XmlAccessorType(XmlAccessType.FIELD)
    public class Project { 
        public String getType() { 
            return type; 
        } 
    
        public void setType(String type) { 
            this.type = type; 
        } 
    
        private String type; 
    
        @XmlElement(name = "compilation-unit") 
        private CompilationUnit compilation_unit; 
    
        public CompilationUnit getPckg() { 
            return compilation_unit; 
        } 
    
        public void setPckg(String pckg) { 
            this.compilation_unit = compilation_unit; 
        } 
    
    }
    

    仅供参考,下面是一篇关于@XmlPath 注解的文章:

    【讨论】:

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