在 SQLite 中使用 WITH 子句和 INTERSECT 时出错

Question

我有两个 SQL 查询； 第一个是：

with b as (select person_id from people where name='Ward Bond' and born=1903)
select title_id from b natural join crew;

这会产生正确的结果并且可以。 另一个是：

with c as (select person_id from people where name='John Wayne' and born=1907)
select title_id from c natural join crew;

这也完全可以并产生正确的结果。一旦我尝试使用以下查询找到这两个查询的交集：

with b as (select person_id from people where name='Ward Bond' and born=1903) select title_id from b natural join crew 
intersect
with c as (select person_id from people where name='John Wayne' and born=1907) select title_id from c natural join crew;

我收到错误Error: near "with": syntax error 我正在使用 SQLite3。你能帮我找出问题吗？我想要得到的东西很简单；我想要这两个临时表的交集。

Answer 1

这是 SQLite 的正确语法：

select * from (
  with b as (
    select person_id 
    from people 
    where name='Ward Bond' and born=1903
  ) 
  select title_id from b natural join crew
)
intersect
select * from (
  with c as (
    select person_id 
    from people 
    where name='John Wayne' and born=1907
  ) 
  select title_id from c natural join crew
);

另一种获取相交行的方法：

with cte(name, born) as (values ('Ward Bond', 1903), ('John Wayne', 1907))
select c.title_id 
from crew c natural join people p
where (p.name, p.born) in cte
group by c.title_id
having count(distinct p.person_id) = 2;

Answer 2

我就是这样使用view：

create view a as select person_id from people where name='Ward Bond' and born=1903;
create view b as select person_id from people where name='John Wayne' and born=1907;
with c as 
(select title_id from a natural join crew
intersect
select title_id from b natural join crew) 
select primary_title from c natural join titles;