无法计算字符

Question

我无法理解这里的问题，所以我希望有人能帮忙 我有这样的程序开始 int main():

    Board br;
    GetNames();
    br.PresentPlayer();

    system("PAUSE");
    return 0;

GetNames() 看起来像这样：

char p[100];
char p2[100];
Board br;
cout << "Please Enter Player 1's Name:";
cin >> _player_name_1;
cout << "Please Enter " << _player_name_1 << "'s Symbol(Make sure its 1 characters long):";
cin >> p;
cout << "Please Enter Player 2's Name:";
cin >> _player_name_2;
cout << "Please Enter " << _player_name_2 << "'s Symbol(Make sure its 1 characters long):";
cin >> p2;
br.SetSymbols(p[0], p2[0]);

Board::SetSymbols(char p,char p2) 看起来像这样：

void Board::SetSymbols(char p1,char p2)
{
_player_char_1 = p1;
_player_char_2 = p2;
_current_player = _player_char_1;
cout << _current_player << endl;
}

变量在 Board.h 中：

char _player_char_1;
char _player_char_2;
char _current_player;

最后是 PresentPlayer()：

void Board::PresentPlayer()
{
cout << _current_player << endl;

}

所以当 SetSymbols 被执行时，它会正确打印出 _player_char_1 但是，当 PresentPlayer 被执行时，它会打印出你会执行此操作的那些符号 alt+numlock 数字

为什么会这样？？

Answer 1

char _player_char_1;
char _player_char_2;
char _current_player;

应该是

char *_player_char_1;
char *_player_char_2;
char *_current_player;

或者，由于您使用的是 C++，stop 使用 char*（您没有为它们分配内存或检查边界），而是使用 std::string。

void Board::SetSymbols(char p1,char p2)

需要

void Board::SetSymbols(char *p1,char *p2)

甚至更好

void Board::SetSymbols(std::string &p1, std::string &p2)