【问题标题】:C# XML Serializable CollectionC# XML 可序列化集合
【发布时间】:2012-04-09 19:57:49
【问题描述】:

我得到了下面的 XML(它只是我遇到问题的大型 XML 的一部分),我正在尝试制作一个 Serializable 类来读取它。

<BANKTRANLIST>
  <DTSTART>20051001</DTSTART>
  <DTEND>20051028</DTEND>
  <STMTTRN> <!-- This element can repeat any number of times -->
    <TRNTYPE>CHECK</TRNTYPE>
    <DTPOSTED>20051004</DTPOSTED>
    <TRNAMT>-200.00</TRNAMT>
  </STMTTRN>
  <STMTTRN>
    <TRNTYPE>ATM</TRNTYPE>
    <DTPOSTED>20051020</DTPOSTED>
    <TRNAMT>-300.00</TRNAMT>
  </STMTTRN>
</BANKTRANLIST>

我的 C# 实现

[Serializable]
[XmlRoot("BANKTRANLIST", Namespace = "http://bank.net", IsNullable = false)]
public class BankTransactionList
{
    public BankTransactionList()
    {
        this.StatementTransactions = new List<StatementTransaction>();
    }

    [XmlElement("DTSTART")]
    public string StartDate { get; set; }

    [XmlElement("DTEND")]
    public string EndDate { get; set; }

    [XmlArray("STMTTRN")]
    [XmlArrayItem("STMTTRN")]
    public List<StatementTransaction> StatementTransactions { get; set; }
}


[Serializable]
[XmlRoot("STMTTRN", Namespace = "http://bank.net", IsNullable = false)]
public class StatementTransaction
{
    // TransactionType : ENUM
    [XmlElement("TRNTYPE")]
    public TransactionType TransactionType { get; set; }

    [XmlElement("DTPOSTED")]
    public string DatePosted { get; set; }

    [XmlElement("TRNAMT")]
    public double TransactionAmount { get; set; }
}

我的问题是元素再次包裹在元素中,结果得到以下输出

...
    <STMTTRN> <!-- This does not match my Original XML -->
      <STMTTRN>
        <TRNTYPE>CHECK</TRNTYPE>
        <DTPOSTED>20051004</DTPOSTED>
        <TRNAMT>-200.00</TRNAMT>
      </STMTTRN>
      <STMTTRN>
        <TRNTYPE>ATM</TRNTYPE>
        <DTPOSTED>20051020</DTPOSTED>
        <TRNAMT>-300.00</TRNAMT>
      </STMTTRN>
    </STMTTRN>

注意:从 List 属性中删除 [XmlArray("STMTTRN")] 标记将无法解决此问题,而是

如果有人可以纠正我或给我一个更好的解决方案,那就太好了!

【问题讨论】:

    标签: c# list xml-serialization ofx


    【解决方案1】:

    如果您希望每个项目都有一个元素而没有包装器元素,则应为 [XmlElement]

    [XmlElement("STMTTRN")]
    public List<StatementTransaction> StatementTransactions { get; set; }
    

    【讨论】:

      【解决方案2】:

      我要补充一点,为了序列化你需要这样的集合:

      [Serializable]
      [XmlRoot("BANKTRANLIST", Namespace = "http://bank.net", IsNullable = false)]
      public class BankTransactionList
      {
          public BankTransactionList()
          {
              StatementTransactions = new List<StatementTransaction>()
              {
                  new StatementTransaction()
              };
          }
      
          [XmlElement("DTSTART")]
          public string StartDate { get; set; }
      
          [XmlElement("DTEND")]
          public string EndDate { get; set; }
      
          [XmlElement("STMTTRN")]
          public List<StatementTransaction> StatementTransactions { get; set; }
      }
      

      否则,如果不初始化StatementTransaction对象,列表将不会被序列化。

      【讨论】:

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