EF Core 2.1.1 带有构造函数调用的种子方法

Question

为什么种子类的构造函数中设置的属性等于0？我有自己的种子方法：

    public static void Seed(this ModelBuilder modelBuilder)
    {
        Random random = new Random();
        int range = 20; // for doubles

        int countOfWorkers = 10;

        modelBuilder.Entity<Farm>().HasData(Farm.GetFarm());

        for (int i = 0; i < countOfWorkers; i++)
        {
            modelBuilder.Entity<Driver>().HasData(
            new Driver
            {
                // i belive that constructor launch in here
                Id = i + 1,
                FarmId = 1,
                FirstName = "name" + i,
                LastName = "lastname" + i,
                UsdPerHour = Math.Round((random.NextDouble() * 20), 2),
                HoursPerDay = random.Next(1, 23),
                DaysOfWork = random.Next(1, 31)
            });
        }
    }

Driver 类有一个构造函数：

public class Driver : Worker
{
    // constructor
    public Driver() => BaseSalary = CountBaseSalary();

    public override double BaseSalary { get; set; }

    //this propertys like UsdPerHours are in my abstract 'Worker' class
    public override double CountBaseSalary() => UsdPerHour* HoursPerDay *DaysOfWork;

}

该设置值 BaseSalary 基于 Seed 的属性，例如 UsdPerHour、DaysOfWork 等。

根据上面的代码，我在数据库中的BaseSalary 属性设置为'0'，所有行

我的问题是，当我开始播种我的数据时，我的方法CountBaseSalary 是否来自构造函数？是否有可能在此方法所需的行之后以某种方式运行方法CountBaseSalary？在哪里转换我的方法以获得我想要的价值？

Answer 1

对于Class，Constructor 在Properties initialize 之前调用。因此，您应该避免根据其他属性从Constructor 设置属性值。

试试

for (int i = 0; i < countOfWorkers; i++)
{
    var driver = new Driver
    {
        // i belive that constructor launch in here
        Id = i + 1,
        FirstName = "name" + i,
        LastName = "lastname" + i,
        UsdPerHour = Math.Round((random.NextDouble() * 20), 2),
        HoursPerDay = random.Next(1, 23),
        DaysOfWork = random.Next(1, 31)
    };
    driver.BaseSalary = driver.CountBaseSalary();
    modelBuilder.Entity<Driver>().HasData(driver);
}