【问题标题】:Getting errors when trying to seed tables in Laravel尝试在 Laravel 中播种表时出错
【发布时间】:2021-09-07 10:37:42
【问题描述】:

当我尝试执行 php artisan migrate:fresh --seed 命令时,我遇到了错误。我不明白它们的全部含义,也不知道是什么原因造成的。问题描述如下。

工厂文件 PostFactory.php:

<?php

namespace Database\Factories;

use App\Models\Post;
use Illuminate\Database\Eloquent\Factories\Factory;

class PostFactory extends Factory
{
    /**
     * The name of the factory's corresponding model.
     *
     * @var string
     */
    protected $model = Post::class;

    /**
     * Define the model's default state.
     *
     * @return array
     */
    public function definition()
    {
        $title = $faker->realText(rand(10, 40));
        $short_title = \Illuminate\Support\Str::length($title) > 30 ? mb_substr($title, 0, 30) . "..." : $title;
        $created = $faker->dateTimeBetween("-30days", "-1days");

        return [
            "title" => $title,
            "short_title" => $short_title,
            "author_id" => rand(1, 4),
            "descr" => $faker->realText(100, 500),
            "created_at" => $created,
            "updated_at" => $created
        ];
    }
}

DatabaseSeeder.php:

<?php

namespace Database\Seeders;

use Illuminate\Database\Seeder;

class DatabaseSeeder extends Seeder
{
    /**
     * Seed the application's database.
     *
     * @return void
     */
    public function run()
    {
        \App\Models\User::factory()->count(4)->create();
        \App\Models\Post::factory()->count(15)->create();
    }
}

当我执行 php artisan migrate:fresh --seed 时出现这些错误:

Illuminate\Database\QueryException 

  SQLSTATE[HY000] [2002]   , ..      .
 (SQL: SHOW FULL TABLES WHERE table_type = 'BASE TABLE')

  at C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connection.php:692
    688▕         // If an exception occurs when attempting to run a query, we'll format the error
    689▕         // message to include the bindings with SQL, which will make this exception a   
    690▕         // lot more helpful to the developer instead of just the database's errors.     
   Illuminate\Database\QueryException 

  SQLSTATE[HY000] [2002]   , ..      .
 (SQL: SHOW FULL TABLES WHERE table_type = 'BASE TABLE')

  at C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connection.php:692
    688▕         // If an exception occurs when attempting to run a query, we'll format the error
    689▕         // message to include the bindings with SQL, which will make this exception a
    690▕         // lot more helpful to the developer instead of just the database's errors.
    691▕         catch (Exception $e) {
  ➜ 692▕             throw new QueryException(
    693▕                 $query, $this->prepareBindings($bindings), $e
    694▕             );
    695▕         }
    696▕

  1   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.php:70
      PDOException::("SQLSTATE[HY000] [2002]   , ..      .
")

  2   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.php:70
      PDO::__construct("mysql:host=localhost;port=3306;dbname=laralove", "root", "", [])

我已经检查了错误描述中提供的文件中的行,但我不知道是什么导致了错误。

任何帮助都会非常感激


UPD 0:

我已尝试按照@Rwd 的建议将配置文件中的“localhost”更改为“127.0.0.1”。以前的错误消失了。但现在我遇到了其他错误:

ErrorException 

  Undefined variable: faker

  at C:\xampp\htdocs\laralove\database\factories\PostFactory.php:24
     20▕      * @return array
     21▕      */
     22▕     public function definition()
     23▕     {
  ➜  24▕         $title = $faker->realText(rand(10, 40));
     25▕         $short_title = \Illuminate\Support\Str::length($title) > 30 ? mb_substr($title, 0, 30) . "..." : $title;
     26▕         $created = $faker->dateTimeBetween("-30days", "-1days");
     27▕
     28▕         return [

  1   C:\xampp\htdocs\laralove\database\factories\PostFactory.php:24
      Illuminate\Foundation\Bootstrap\HandleExceptions::handleError("Undefined variable: faker", "C:\xampp\htdocs\laralove\database\factories\PostFactory.php", [])

  2   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Eloquent\Factories\Factory.php:385
      Database\Factories\PostFactory::definition()

UPD 1:

按照@Cristea 的建议将$faker 替换为$this-&gt;faker,现在得到了以前的错误:

  1   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.php:70
      PDOException::("SQLSTATE[HY000] [2002]   , ..      .
")

  2   C:\xampp\htdocs\laralove\vendor\laravel\framework\src\Illuminate\Database\Connectors\Connector.php:70
      PDO::__construct("mysql:host=localhost;port=3306;dbname=laralove", "root", "", [])

正如@Rwd 建议的那样,localhost 仍然在 .env 和 database.php 中更改为 127.0.0.1

【问题讨论】:

  • 与数据库的连接是否正常?
  • @Cristea 是的,database.php 和 .env 文件配置正确
  • 尝试将定义值更改为一些字符串而不是变量,看看会发生什么。
  • 尝试将localhost 更改为127.0.0.1
  • 其他可能的解决方案: 1. 每次更改.env 文件时都需要运行php artisan config:cache。 2. 如果作者表不存在,请确保App\Models\Post 具有外键author_iduser_id。例如:public function author() {return $this-&gt;belongsTo(User::class, 'user_id'); } 3. 尝试测试与数据库的连接是否真的有效。 4.检查是否有更多版本的mysql

标签: php laravel seeding factories


【解决方案1】:

只需将$faker 替换为$this-&gt;faker

【讨论】:

  • 感谢您的回答。我已经尝试过了,但遇到了其他错误
  • 请查看我在问题中的最新更新
  • 但是你能解释一下为什么我应该写$this-&gt;faker而不是$faker吗?在这样做并写了php artisan config:cache之后它现在工作正常,但我真的很想了解为什么会这样
  • 在我看过的教程中,它被写成 $faker 并且一切正常(本教程是 2 年前制作的,也许 Laravel 中有所改变)
  • 您可以通过这种方式访问​​它的原因是因为您扩展了class Factory,它具有faker 作为属性。您正在观看的教程可能是使用旧版本的`laravel`并通过导入访问faker
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