c ++变量重新分配被代码忽略[关闭]

Question

我不是专业程序员，但是在获得了一些简单的语言（如 python 或 matlab）的经验后，我需要用 C++ 编写一个小程序。为此，我尝试读取用户输入，直到用户输入合理的内容 - 但是，由于我的控制变量 (test2) 从未被重新分配，即使输入了相应的代码块，此循环也不会终止。让我详细解释一下：

#include <iostream>
#include <string>
#include <sstream>
#include <vector>
#include "Header.h"

using namespace std;

int test2; //variable to stay 1 until user has entered suitable input
string input2[2]; //storage for input strings

int MinimalTest() {
  test2 = 1; //control variable is set one
  cout << "Enter a string." << endl;
  do {
     //we will enter a string at least once, and we exit this loop only when the input is suitable
      std::string line; //complicated input part - a simple getline() command led to weird behaviour 
      std::getline(std::cin, line);
      std::stringstream linestream(line);
      linestream >> input2[i];
      cout << "input: " << input2[i] << " test: " << test2 << "input bool: " << input2[i].empty() << endl; //this is just for troubleshooting

      if (input2[i].empty()) {
        //if the user entered an empty string, he needs to do it again
          cout << "Your string is empty. Please enter a valid string (non-empty)." << endl;
      }
      else {
        //if he entered a valid string, we can continue with the next input
          cout << "I am here." << endl; //This is for trouble shooting. This code block is entered and executed since this gets printed.
          test2 = 0;// this gets ignored for some reason. Hence, the loop never terminates.
      }
  }(while (test2 = 1);
}

所以第一个循环永远不会终止。即使执行了 else 命令，Test2 也永远不会重新分配为 0。这让我大吃一惊——它只是一个简单的 int 赋值运算符。可能的输出如下所示（请注意我仍然遇到第二个问题：内部有空格的字符串被切断。我也将不胜感激任何反馈，即使我尝试一次解决一件事并且这篇文章是不是针对这个问题）：

Output example

非常感谢您的考虑！

一切顺利，

一个非常困惑的新手。

Answer 1

将您的 while 条件更改为 test2 == 1

test2 = 1 是一个赋值，将值设置为 1。