石头剪刀布 PYTHON答案

【问题标题】：Rock Paper Scissors PYTHON石头剪刀布 PYTHON
【发布时间】：2018-04-06 23:25:07
【问题描述】：

Python 石头剪刀布非常适合我。我只是有点困惑如何将“人类”使用每种武器的次数加起来并打印出来……

from random import choice

win = 0
loss = 0
tie = 0


rules = {'Rock': 'Paper', 'Scissors': 'Rock', 'Paper': 'Scissors'}
previous = ['Rock', 'Paper', 'Scissors']


while True:
 human = input('Rock, Paper, Scissors or Quit???: ')
 computer = rules[choice(previous)]  

if human in ('Quit'):
    print("YoU WoN %d TiMEs!" % win)
    print("yOu lOSt %d tImEs!" % loss)
    print("YoU TIeD %d TiMEs!" % tie)
    print("SeE YoU LaTeR!!! :)")

elif human in rules:
    previous.append(human)
    print('tHe CoMPuTeR PlAyEd', computer, end='; ')

    if rules[computer] == human:  
        print('YoU WiN!')
        win += 1
    elif rules[human] == computer:  
        print('ThE CoMpUtER BeAT YOU!!!')
        loss += 1
    else:
        print("It'S A tIE!")
        tie += 1

else: print("that's not a valid choice")

【问题讨论】：

标签： python loops if-statement random while-loop

【解决方案1】：

import random

c1=[0];p1=[0];t=1
result={-1:p1,-2:c1,1:c1,2:p1,0:[0]}
opt=["exit","Rock","Paper","Scissors",]

while 1:
    print("\n","-"*30,sep="")   
    comp= random.randint(1,3)   
    user=input("Choose Option\n1. %s 2. %s 3. %s 0. %s\n>>"%(opt[1],opt[2],opt[3],opt[0]))
    if user not in ['1','2','3']:break
    user=int(user)
    print("Comp--> %s -- %s <--You"%(opt[comp],opt[user]))    
    g=result[comp-user]
    g[0]+=1
    print("\n---Score---\nComp--> %s\nYou--> %s\n----------"%(c1[0],p1[0]))    
print("\n------------------\n %s won!\n------------------"%("Computer" if c1[0]>p1[0] else "You"))

【讨论】：

给出答案很好，但如果你解释它会更好

【解决方案2】：

您可以使用带有武器的字典作为键，每次选择它们时都会更新。字典将在 while 循环之前以 0 个计数预先初始化，

human_choices = {'Rock': 0, 'Paper': 0, 'Scissors': 0};

然后您可以在选中 Quit 选项后更新 elif 中的条目：

elif human in rules:
        human_choices[human]+=1
        previous.append(human)

您可以在 Quit if 中打印计数：

    print(human_choices)

附带说明，如果您希望程序在输入Quit 后真正结束，您需要在 Quit-if 的末尾添加 break 语句：

    print("SeE YoU LaTeR!!! :)")
    break

【讨论】：

如果你能提供帮助，我认为你不应该从你的代码中调用exit(0)。如果出现问题，它主要用于设置退出代码 (exit(1))
@Adam Smith 谢谢，我删除了它。尽管如果您认为这样做很好，我可以包括您的评论。通常我会使用break，但我认为在那个位置退出可能会有一些好处，因为while循环似乎是代码的逻辑结束。

【解决方案3】：

这是你要找的吗？：

from random import choice

win = 0
loss = 0
tie = 0
humanRocks = 0  
humanScissors = 0
humanPapers = 0

rules = {'Rock': 'Paper', 'Scissors': 'Rock', 'Paper': 'Scissors'}
previous = ['Rock', 'Paper', 'Scissors']

while True:
   human = input('Rock, Paper, Scissors or Quit???: ')
   computer = rules[choice(previous)]  
  if human in ('Quit'):
    print("YoU WoN %d TiMEs!" % win)
    print("yOu lOSt %d tImEs!" % loss)
    print("YoU TIeD %d TiMEs!" % tie)
    print("You used Rocks %d times" % humanRocks)
    print("You used Paper %d times" % humanPapers)
    print("You used Scissors %d times" % humanScissors)
    print("SeE YoU LaTeR!!! :)")
    exit(0)
elif human in rules:
    previous.append(human)
    print('tHe CoMPuTeR PlAyEd', computer, end='; ')

    if rules[computer] == human:  
       print('YoU WiN!')
       win += 1
    elif rules[human] == computer:  
       print('ThE CoMpUtER BeAT YOU!!!')
       loss += 1
    else:
       print("It'S A tIE!")
       tie += 1
    if human == "Rock":
       humanRocks+=1
    elif human == "Paper":
       humanPapers+=1
    elif human == "Scissors":
       humanScissors+=1 

    else: print("that's not a valid choice")

【讨论】：