PHP随机替换单词

Question

我有一个名为 $featuresSEO 的数组，其中包含许多单词，例如：

Array (
    [0] => Japan 
    [1] => Japanese 
    [2] => Tokyo 
    [3] => Yokohama 
    [4] => Osaka 
    [5] => Asian 
    [6] => Nagoya 
) 

然后我有一个如下字符串：

 Searching the |*-*| Dating membership database is the key to locating |*-*| people
 you would be interested in. You can search for |*-*| Singles including |*-*| Women
 and |*-*| Men in any location worldwide. Join now to search for |*-*| Singles.

我一直在尝试用数组中的随机单词替换 |*-*| 的实例。我试过 str_replace() 但无法让随机方面工作。

有人能把我推向正确的方向吗？

谢谢

Answer 1

PHP 已经有一个本机函数，它允许您用字符串数组替换模板字符串中的占位符 -- vprintf() 从格式打印变量 如果我没记错的话。

如果您最初使用可识别的占位符设置模板，则无需调用 str_replace()。

代码：(Demo)

$template = 'Searching the |*-*| Dating membership database is the key to locating |*-*| people
 you would be interested in. You can search for |*-*| Singles including |*-*| Women
 and |*-*| Men in any location worldwide. Join now to search for |*-*| Singles.';

$array = ['Japan', 'Japanese', 'Tokyo', 'Yokohama', 'Osaka', 'Asian', 'Nagoya'];

shuffle($array);
vprintf(str_replace('|*-*|', '%s', $template), $array);

潜在输出：

Searching the Asian Dating membership database is the key to locating Japan people
 you would be interested in. You can search for Osaka Singles including Nagoya Women
 and Yokohama Men in any location worldwide. Join now to search for Tokyo Singles.

Answer 2

我希望这仍然是相关的）

$wordarray = [
   'some',
   'random',
   'words',
   'list'
];
shuffle($wordarray);
$string = implode(' ', $wordarray);

您可以将 implode 更改为 sprintf，这是我的实现。

Answer 3

试试这个

$string = ' Searching the |*-*| Dating membership database is the key to locating |*-*| people
 you would be interested in. You can search for |*-*| Singles including |*-*| Women
 and |*-*| Men in any location worldwide. Join now to search for |*-*| Singles.';

$words = array('Japanese', 'Tokyo', 'Asian');

$placeholder = '|*-*|';
$pos = null;

while(null === $pos || false !== $pos) {
    $pos = strpos($string, $placeholder);
    $string = substr_replace($string, $words[rand(0, count($words)-1)], $pos, strlen($placeholder));

}

echo $string;

第一个单词出乎意料

Answer 4

replace-only-first-match 的代码是从here 借来的。以下代码仅使用列表中的每个单词一次：

$wordlist = array(
    'Japan',
    'Japanese',
    'Tokyo',
    'Yokohama',
    'Osaka',
    'Asian',
    'Nagoya'
);
$string = "
Searching the |*-*| Dating membership database is the key to locating |*-*| people
you would be interested in. You can search for |*-*| Singles including |*-*| Women
and |*-*| Men in any location worldwide. Join now to search for |*-*| Singles.
";
$replace = '|*-*|';
while(true){
    $index = strpos($string, $replace);
    if($index === false){
        // ran out of place holder strings
        break;
    }
    if(count($wordlist) == 0){
        // ran out of words
        break;
    }
    $word = array_splice($wordlist, rand(0, count($wordlist) - 1), 1);
    $string = substr_replace($string, $word[0], $index, strlen($replace));
}
echo $string;

Answer 5

试试这个

<?php
    $array = array("Japan","Japanese","Tokyo","Yokohama","Osaka","Asian","Nagoya");
    $a = array_rand($array);
    $string= "abc|*-*|";
    echo str_replace("|*-*|", $array[$a], $string);
?>

Answer 6

一一替换。这将用一个随机单词替换每个出现。您可能会多次看到来自 $wordarray 的同一个词，因为它每次都会随机选择 1。

for ($i = 0; $i < substr_count($string, '|*-*|'); $i++){
     $string = preg_replace('/\|\*-\*\|/',$wordarray[rand(0,count($wordarray)-1)],$string, 1);
}

希望每个单词只使用一次？打乱数组，并循环遍历它：

shuffle($wordarray);
foreach ($wordarray as $word){
    $string = preg_replace('/\|\*-\*\|/',$word,$string,1);
}