【发布时间】：2019-05-09 09:48:15
【问题描述】：
我正在尝试制作数学乘法应用程序。Learninig Unity 和 c#。使用 Random.range 为答案按钮分配一个正确答案和 3 个随机值。但是，有时会将重复值分配给答案按钮。我的意思是为两个或有时三个答案按钮分配了相同的值。我附上了屏幕截图。任何人都可以帮我解决这个问题吗？谢谢
public class Multplication : MonoBehaviour {
//we make this script instance
public static Multplication instance;
//its an enum which we help use to identify the current mode of game
public enum MathsType
{
multiplication1to10,
multiplication11to20
}
//we make a variable of MathsType
public MathsType mathsType;
//2 private floats this are the question values a and b
private float a, b ;
//the variable for answer value
[HideInInspector] public float answer;
//varible whihc will assign ans to any one of the 4 answer button
private float locationOfAnswer;
//ref to the button
public GameObject[] ansButtons;
//ref to image symbol so player can know which operation is to be done
public Image mathSymbolObject;
//ref to all the symbol sprites whihc will be used in above image
public Sprite[] mathSymbols;
//get the tag of button
public string tagOfButton;
//varible to check whihc mode is this
private int currentMode;
//ref to text in scene where we will assign a and b values of question
public Text valueA , valueB;
void Awake()
{
MakeInstance();
}
//method whihc make this object instance
void MakeInstance()
{
if (instance == null)
{
instance = this;
}
}
//at start we need to do few basic setups
void Start ()
{
//we put the location value in tag of button variable
tagOfButton = locationOfAnswer.ToString();
if (GameManager.singleton != null)
{
//get whihc mode is selected
currentMode = GameManager.singleton.currentMode;
}
//we call the methods
CurrentMode();
MathsProblem();
}
//this method keeps the track of mode
void CurrentMode()
{
if (currentMode == 4)
{
//depending on the currentmode value we assign the mode
mathsType = MathsType.multiplication1to10;
}
else if (currentMode == 5)
{
mathsType = MathsType.multiplication11to20;
}
}
// Update is called once per frame
void Update ()
{
tagOfButton = locationOfAnswer.ToString();
}
//this methode calls the respective method for the respective mode
public void MathsProblem()
{
//switch case is used to assign method
switch (mathsType)
{
case (MathsType.multiplication1to10):
Multiplication1to10();
break;
case (MathsType.multiplication11to20):
Multiplication11to20();
break;
}
}
//this methode perform Multiplication process
void MultiplicationMethod()
{
b = Random.Range(0, 10);
locationOfAnswer = Random.Range(0, ansButtons.Length);
answer = a * b;
valueA.text = ("" + a).ToString();
valueB.text = ("" + b).ToString(); ;
mathSymbolObject.sprite = mathSymbols[0];
for (int i = 0; i < ansButtons.Length; i++)
{
if (i == locationOfAnswer)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + answer;
}
else
{
// the below code make sure that all the values assigned to the ans button are within the range
if (a * b <= 30)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range( 0, 30);
}
else if (a * b <= 60 & a * b >= 31)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(28, 61);
}
else if (a * b <= 90 & a * b >= 61)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(58, 91);
}
else if (a * b <= 120 & a * b >= 91)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(88, 121);
}
else if (a * b <= 150 & a * b >= 121)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(118, 151);
}
else if (a * b <= 200 & a * b >= 151)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(148, 201);
}
while (ansButtons[i].GetComponentInChildren<Text>().text == "" + answer)
{
ansButtons[i].GetComponentInChildren<Text>().text = "" + Random.Range(0, 201);
}
}
}
}
void Multiplication1to10()
{
a = Random.Range(1, 10);
MultiplicationMethod();
}
void Multiplication11to20()
{
a = Random.Range(11, 20);
MultiplicationMethod();
}
}
【问题讨论】：
-
每次你选择一个随机数时，检查它是否已经被选择（或者它是否匹配正确的答案）。如果它已被选中，则选择一个不同的数字。继续检查和挑选，直到没有重复。只有四个数字（1 个答案，3 个随机），只要您的范围足够宽，这并不难。
-
@rossum 谢谢你的建议。是的，我明白这一点，但不知道如何相互比较随机值。我可以使用哪种方法？
-
要获得三个唯一的数字，请尝试以下代码： Random rand = new Random(); int[] number = Enumerable.Range(0, 10).Select(x => new { x = x, i = rand.Next() }).OrderBy(x => xi).Select(x => xx) .ToArray(); int number1 = number[0]; int number2 = number[1]; int number3 = number[2];
-
@rossum：最好只创建一个唯一编号的数组然后排序。然后从排序数组中取出前三个数字。
-
@jdweng 对于随机我更喜欢随机排列的数组。对其中三个数字进行排序可能会使正确答案脱颖而出：“1、2、42、3”。我认为更简单的技术可能更容易，并且您仍然需要在改组之前从数组中删除正确的答案。
标签： c# unity3d random duplicates multiplication