前面已经提到,从当前迭代的集合中删除元素时必须小心。这可能很容易导致ConcurrentModificationException。对于不能轻易使用迭代器的“复杂”情况,通常可以应用的模式是,而不是做类似的事情
Collection<Element> collection = ...
for (Element element : collection)
{
if (hasToBeRemoved(element))
{
// Will cause a ConcurrentModificationException!
collection.remove(element);
}
}
你收集要移除的元素,一次性全部移除
Collection<Element> collection = ...
Collection<Element> elementsToRemove = new List<Element>();
for (Element element : collection)
{
if (hasToBeRemoved(element))
{
elementsToRemove.add(element);
}
}
collection.removeAll(elementsToRemove);
根据代码,您似乎尝试过类似的操作,使用您的keys_to_delete,但这并不完全清楚。
正如评论中提到的,您应该考虑使用专用数据结构进行替换等。但即使您希望为此目的坚持使用列表和地图,您也应该始终使用 接口在声明中。所以而不是
ArrayList<HashMap<Character,Character>> allKeys = ...
你应该写
List<Map<Character,Character>> allKeys = ...
但是,关于实际问题:似乎可以通过引入像 computeKeysContaining(maps, entry) 这样的方法来解决主要问题,该方法返回给定集合中包含特定条目的所有地图。
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.LinkedHashSet;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
public class MapListKeyRemoval
{
public static void main(String[] args)
{
List<Map<Character,Character>> allKeys = generateAllCombinations();
print("All keys", allKeys);
Set<Map<Character,Character>> keysToDelete =
new LinkedHashSet<Map<Character,Character>>();
for (Map<Character, Character> key : allKeys)
{
for (Entry<Character, Character> entry : key.entrySet())
{
if (isInvalidMapping(entry))
{
System.out.println("Invalid mapping: "+entry);
Set<Map<Character, Character>> keysWithInvalidMapping =
computeKeysContaining(allKeys, entry);
print("Keys with invalid mapping", keysWithInvalidMapping);
keysToDelete.addAll(keysWithInvalidMapping);
}
}
}
print("Keys to delete", keysToDelete);
allKeys.removeAll(keysToDelete);
print("All keys after removal", allKeys);
}
private static void print(
String message, Iterable<Map<Character,Character>> keys)
{
System.out.println(message);
for (Map<Character, Character> key : keys)
{
System.out.println(key);
}
}
private static Set<Map<Character, Character>> computeKeysContaining(
List<Map<Character,Character>> allKeys,
Entry<Character, Character> entry)
{
Set<Map<Character,Character>> keysContainingEntry =
new LinkedHashSet<Map<Character,Character>>();
for (Map<Character, Character> key : allKeys)
{
Object value = key.get(entry.getKey());
if (value != null && value.equals(entry.getValue()))
{
keysContainingEntry.add(key);
}
}
return keysContainingEntry;
}
private static boolean isInvalidMapping(Entry<Character, Character> entry)
{
return entry.getKey().equals('g') && entry.getValue().equals('h');
}
private static List<Map<Character, Character>> generateAllCombinations()
{
List<Map<Character, Character>> result =
new ArrayList<Map<Character,Character>>();
result.add(createMapping('f','i','r','s','t','-','g','h'));
result.add(createMapping('s','e','c','o','n','d','g','x'));
result.add(createMapping('t','h','i','r','d','-','g','h'));
result.add(createMapping('f','o','u','r','t','h','g','x'));
return result;
}
private static Map<Character, Character> createMapping(char ... c)
{
Map<Character, Character> map =
new LinkedHashMap<Character, Character>();
for (int i=0; i<c.length/2; i++)
{
map.put(c[i*2+0], c[i*2+1]);
}
return map;
}
}
(除此之外,我想知道为什么回答问题的人是那些(必须)为这些简单的问题创建https://stackoverflow.com/help/mcve,但不想推测的人原因在这里)