合并两个 Laravel 集合并对值求和

Question

我有 10 个（以下示例中使用了 3 个）集合，我需要按键合并，但需要对这些值求和。我的收藏是这样的：

[
    'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
    'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
    'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
]

[
    'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
    'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
    'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
]

[
    'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
    'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
    'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
]

我想获得一个结果如下所示的集合：

[
    'key1' => ['value1' => 10, 'value2' => 7, 'value3' => 16],
    'key2' => ['value1' => 5, 'value2' => 17, 'value3' => 7],
    'key3' => ['value1' => 2, 'value2' => 6, 'value3' => 8],
]

我是否缺少内置的 Laravel Collection 方法，或者实现此目的的最佳方法是什么？

编辑：（更多信息）这些值始终是数字。任何集合中都没有字符串值。

edit2：有些人问我试过什么。我已经试过了：

$merged = [];
foreach ($seeds as $seed) {
    foreach ($seed as $location => $values) {
        foreach ($values as $key => $value) {
            $merged[$location][$key] = $value + ($merged[$location][$key] ?? 0);
        }
    }
}

我只是想知道是否有更简洁的方法来实现相同的目标，而不是使用 3 个 foreach 循环。

Answer 1

我用 laravel 7 做了这个，以防它适用于某人

$test = collect([
   [
     'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
     'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
     'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
     'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
     'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
     'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
     'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
   ]
]);
$col = $test->reduce(function ($carry, $item) {
    return $carry->mergeRecursive($item);
}, collect([]));
$col->transform(function($item) {
    return collect($item)->map(function ($item2) {
        return collect($item2)->sum();
    });
});

Answer 2

真的认为会有比循环更容易做的事情，但似乎该解决方案仍然比我想出的解决方案更好。 Flatten 即使改变深度也会移除键，mapToGroups 仅在返回包含单个键/值对的关联数组时有效，pluck 带来一些其他困难等等。

这是我想出来的

$test = collect([
   [
     'key1' => ['value1' => 5, 'value2' => 3, 'value3' => 0],
     'key2' => ['value1' => 1, 'value2' => 6, 'value3' => 2],
     'key3' => ['value1' => 0, 'value2' => 0, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 3, 'value2' => 1, 'value3' => 7],
     'key2' => ['value1' => 1, 'value2' => 3, 'value3' => 2],
     'key3' => ['value1' => 1, 'value2' => 6, 'value3' => 1],
   ],

   [
     'key1' => ['value1' => 2, 'value2' => 3, 'value3' => 9],
     'key2' => ['value1' => 3, 'value2' => 8, 'value3' => 3],
     'key3' => ['value1' => 1, 'value2' => 0, 'value3' => 6],
   ]
]);
$mappedCollection = collect($test->first())->keys()->mapWithKeys(function($item,$key) use($test){
   return[
      $item => $test->map(function ($mapItem, $mapKey) use($item) {         
         return $mapItem[$item];
      })
   ];
})->mapWithKeys(function($item,$key){
   $eachLine = collect($item->first())->keys()->mapWithKeys(function($mapItem) use($item){
      return[ $mapItem => $item->sum($mapItem)  ];
   });       
   return [$key =>  $eachLine];
})->all();

dd($mappedCollection);

集合文档来源https://laravel.com/docs/5.6/collections