如何在node.js中的上一行之后捕获下一次

Question

日志文件有多次发生的某些字符串。我需要使用 node.js 为所有出现的前一个字符串捕获下一行。 例如文件内容：

Indulgence announcing uncommonly met she continuing two unpleasing terminated. Now busy say down the shed eyes roof paid her  
Compile Error  
./aaarty/bbb/cfvcc/dddhjklpi  
Course suffer to do he sussex it window advice. Yet matter enable misery end extent common men should. Her indulgence but assistance favourable cultivated everything collecting  
Compile Error  
./asshtyd/wrfber/ghn/fffh/gh/ikjmlk  
Extended kindness trifling remember he confined outlived if. Assistance sentiments yet unpleasing say  
Compile Error  
./cc/wwwasftbb/kkk/tgfh/pioqascfg/qqq  
Open they an busy they my such high  strong text  

使用 node.js，我需要使用字符串“编译错误”捕获行后的每一行

Answer 1

我明白了：

var fs = require('fs');
var array = 
fs.readFileSync('mylogfile.txt').toString().split("\n");
    for(let i in array) {
       if (array[i] == "Compilation Error")
          {
            let k = parseInt(i)+parseInt(1)
            console.log(array[k])
          }
    }