ORA-01830: 日期格式图片在转换整个输入字符串 01830 之前结束

Question

我的查询：

SELECT COUNT(*)
FROM pd_heat_data
WHERE treatend_act LIKE TO_CHAR(current_date + 1,'YYYY-MM-DD%') AND (
     ( TO_CHAR(TO_DATE(treatend_act,'YYYY-MM-DD HH24:MI:SS'),'HH24:MI:SS') 
> '00:00:00' ) 
AND ( TO_CHAR(TO_DATE(treatend_act,'YYYY-MM-DD HH24:MI:SS'),'HH24:MI:SS') 
< '06:00:00' )
);

表结构：

HeatID         TREATEND_ACT(varchar2)
0001027184     2018-11-23 02:20:25,906
0001027399     2018-11-23 04:45:02,571

系统日期和时间设置：

Short Date: yyyy-MM-dd
Long Date:  dd MMMMM,yyyy
Short Time: hh:mm tt
Long Time:  hh:mm:ss tt
No AM andPM

Answer 1

由于您的查询试图将整个字符串转换为无法被 to_date 函数整体识别的日期格式，您可以尝试先将substr 应用为：

with pd_heat_data( treatend_act ) as
( select '2018-11-23 02:20:25,906' from dual )
select TO_CHAR(
          TO_DATE(substr(treatend_act,1,19),'YYYY-MM-DD HH24:MI:SS')
       ,'HH24:MI:SS') as "Derived Time"
  from pd_heat_data;

Derived Time
------------
  02:20:25

对于确切的查询：

SELECT COUNT(*)
  FROM pd_heat_data
 WHERE treatend_act LIKE TO_CHAR(current_date + 1,'YYYY-MM-DD%') AND (
     ( TO_CHAR(TO_DATE(substr(treatend_act,1,19),'YYYY-MM-DD HH24:MI:SS'),'HH24:MI:SS') 
> '00:00:00' ) 
AND ( TO_CHAR(TO_DATE(substr(treatend_act,1,19),'YYYY-MM-DD HH24:MI:SS'),'HH24:MI:SS') 
< '06:00:00' )
);

或者不需要额外的转换，substr 可以直接应用@Hilarion（感谢他）指出：

SELECT COUNT(*)
  FROM pd_heat_data
 WHERE treatend_act LIKE TO_CHAR(current_date + 1,'YYYY-MM-DD%') 
   AND substr(treatend_act,1,19) > '2018-11-23 00:00:00'  
   AND substr(treatend_act,1,19) < '2018-11-23 06:00:00';

并尽可能尝试将treatend_act 处的数据移动到date 类型的列中。