指针算术不起作用

Question

我正在尝试做一些指针运算，但由于某种原因，指针在退出循环后没有保留地址的变化。

我的输出是重复打印的数组（整个数组）的指针地址不变。

应该是打印一个值的地址，然后在掷骰子后将指针在数组中向前移动那么多位并打印下一次。

编辑：我不是在写一个链表。可以在此处找到我正在尝试做的一个确切示例：TutorialsPoint.com | C - Pointer arithmetic 但是，虽然我可以运行该示例代码并使其完美运行，但我的代码每次都会失败。

编辑 2：请求完整的源代码

项目名称.cpp

#include "TableOfContents.h"
void main()
{
FILE *fp;       //file reader
char board[100] = "  mHk nH l B He Flq p H  hByHlho H B  jr HFB ir j H  F ku gd  H pjB mH x  BF i H  m oB HlHFBhoH BB ";
char *p1, *p2; // player 1 and player 2
int turn = 1;
srand(time(NULL));   // should only be called once

              //    int z[10]; // example of how to make an array
/*
fp = fopen("C:\\Users\\ritol\\Documents\\cities1.txt", "r");
inputLine = "";
inputP = &inputLine; // set inputP to the address for inputLine
*/
p1 = &board[0];
p2 = &board[0];

fp = fopen("C:\\Users\\ritol\\Documents\\outputGameBoard.txt", "w");

while (turn <= 45) //
{
    //output the current turn

    //call the function move for p1
    move(*p1, *p2, turn, board);

    turn++;//TODO: only put this in it's correct place

    //call the function move for p2
    move(*p1, *p2, turn, board);
    //increment turn
    turn++;

    //call output function to output current board to disk file
    output(board, p1, p2, fp);
}

//determine and output the winner

//Wait
scanf("%d", &turn);

}

头文件：

#pragma once
#ifndef TOC
#define TOC
#define _CRT_SECURE_NO_DEPRECATE 
#include<stdio.h>
#include <stdlib.h>
#include <time.h>
/*
Outputs the current game board to file
*/
void output(char *board, char *p1, char *p2, FILE *myfile);

/*
Receives 
*p1 - player 1 pointer
*p2 - player 2 pointer
turn - the argument to determine which player to move
*board - the size of the board
Outputs the player number, randomly generates a move from 1-6 for the player,
determines if the player has landed on an event, and moves accordingly,
checks and handles player collison,
outputs the amount the player moved and where they are now
*/
void move(char **p1, char **p2, int turn, int boardSize);

#endif 

力学.cpp

#include "TableOfContents.h"

void output(char *board, char *p1, char *p2, FILE *myfile)
{
//the loop will exist once  you have reached \0
fprintf(myfile, "%s\n", board);
//TODO: show the player locations 
}


/*
Moves a player and outputs the result of each players move
*/
void move(char **p1, char **p2, int turn, int boardSize)
{
//roll the dice

int r = (int) (1 + (rand() % 5));      // returns a pseudo-random integer     from 1 to 6

//REMOVE: tracer code
if (r > 6 || r == 0) printf("The dice have sinned.\n");

//Apply the dice roll based on whose turn it is
if (turn % 2 == 1)//Odd turn; Player 1's turn
{
    printf("%p ", p1 + r);
    *p1++;
}
else if (turn % 2 == 0) //Even turn; Player 2's turn
{
    printf("%p\n", p2);
    p2 += r;
}
}

Answer 1

这整件事是因为我误读了我应该做的事情。 我应该返回一个 char 指针，而不是函数是 void。

我现在很尴尬，我不介意被删除。

Answer 2

首先，您的 p1 和 p2 变量不会随着对 move 函数的连续调用而改变，因为您是按值传递指针。见What's the difference between passing by reference vs. passing by value?

其次，您需要解决代码中的其他几个错误。这条线就是其中之一。它没有按照您的评论所说的那样做。

int r = 1 + (rand() % 5);      // returns a pseudo-random integer from 1 to 6