如何在jpql jpa中返回具有多个总和的地图？

Question

这是我的查询

select SUM(d.day) as totalDay, SUM(d.month) as totalMonth from record d where d.userId = ?1
Integer getRecod(Long id);

由于查询未返回整数，因此发生错误。我应该用整数替换什么？

Answer 1

解决方案 1： 使用 totalDay 和 totalMonth 创建一个模型，并创建一个全参数构造函数。

public class UserDataModel {
    Long totalDay;
    Long totalMonth;

    public UserDataModel(Long totalDay, Long totalMonth) {
        this.totalDay = totalDay;
        this.totalMonth = totalMonth;
    }
    
    //getter and setter
}

像这样改变你的查询

@Query(value = "select 
new com.package.UserDataModel(SUM(d.day) as totalDay, SUM(d.month) as totalMonth) 
from Record d where d.userId = ?1 ")
    UserDataModel getRecord(Long id);

解决方案 2：使用弹簧投影。像这样创建一个界面。确保遵循正确的 camcelCase。

public interface UserDataModelV2 {
    Long getTotalDay();
    Long getTotalMonth();
}

像这样改变你的方法。

    @Query(value = "select " +
            " SUM(d.day) as totalDay, SUM(d.month) as totalMonth " +
            "from Record d where d.userId = ?1")
    List<UserDataModelV2> getRecord(Long id);

如果要返回 HashMap 而不是 POJO，可以使用 hashMap 扩展 UserDataModel，并在构造函数中将数据放入映射中。

public class UserDataModel extends HashMap<String, Object>{
    Long totalDay;
    Long totalMonth;

    public UserDataModel(Long totalDay, Long totalMonth) {
        this.totalDay = totalDay;
        this.totalMonth = totalMonth;
        put("totalDay",totalDay); 
        put("totalMonth",totalMonth); 
    }
    
    //getter and setter
}

或者您可以将解决方案 2 中的接口替换为 Map。

@Query(value = "select " +
            " SUM(d.day) as totalDay, SUM(d.month) as totalMonth " +
            "from Record d where d.userId = ?1")
    List<Map<Stirng, Object>> getRecord(Long id);

Answer 2

您应该将 Integer 替换为 Object[] ：

Object[] getRecod(Long id);

因为SUM(d.day) as totalDay, SUM(d.month) as totalMonth在数组中返回两个长值