从文件中删除与模式匹配的行之间的行

Question

如果这是我的文件：

This part can stay
START ALPHA
This should be deleted
And this too
END ALPHA
This should stay
START BETA
This should be deleted
END BETA
This should stay

应该删除“START (whatever)”和“END (whatever)”行之间的所有内容。

我该怎么做？我可以使用 sed、perl、python，任何可行的方法。

Answer 1

使用ed(1) 或sed(1) 脚本：

$ cat filter.sh
#!/bin/sh
exec sed "/START $1/,/END $1/d" data.txt
$ filter.sh ALPHA
This part can stay
This should stay
START BETA
This should be deleted
END BETA
This should stay
$ filter.sh BETA
This part can stay
START ALPHA
This should be deleted
And this too
END ALPHA
This should stay
This should stay
$ _

$ 符号是 shell 提示符，我想你会明白的。 filter.sh 是执行您想要的操作的脚本。