如何使用 PHP 动态过滤网站内容答案

【问题标题】：how to dynamically filter website content using PHP如何使用 PHP 动态过滤网站内容
【发布时间】：2011-04-05 10:53:00
【问题描述】：

我目前正在寻找动态过滤网站内容的解决方案。通过“动态”，我的意思是我会计算坏词的百分比，即shit、f**k 等在第一页的整个单词中的百分比。如果百分比不超过 30%，则表示允许该网站。我如何让它搜索第一页上的每个单词并将它们与坏单词列表匹配，然后除以单词的总数，这样我就可以得到百分比？基本原理不是制作内容过滤器，而是阻止网站，即使页面中的单个单词与坏词列表匹配。虽然我有这个，但它是静态的。

$filename =   "filters.txt";

$fp = @fopen($filename, 'r');

if ($fp) {

$array = explode("\n", fread($fp, filesize($filename)));

foreach($array as $key => $val){

list($before,$after) = split("~",$val);

$input = preg_replace($before,$after,$input);

}
}

*filter.txt包含坏词列表

感谢埃里斯科！

试过了，但它似乎不起作用。

function get_content($url)
{
   $ch = curl_init();

   curl_setopt ($ch, CURLOPT_URL, $url);
   curl_setopt ($ch, CURLOPT_HEADER, 0);

   ob_start();

   curl_exec ($ch);
   curl_close ($ch);
   $string = ob_get_contents();

   ob_end_clean();

   return $string;    

}


/* $toLoad is from Browse.php */

$sourceOfWebpage = get_content($toLoad);
$textOfWebpage = strip_tags($sourceOfWebpage);

/* array: Obtained by your filter.txt file */
// Open the filters file and filter all of the results.

$filename =   "filters.txt";
$badWords = @fopen($filename, 'r');

if ($badWords) {
  $array = explode("\n", fread($fp, filesize($filename)));

  foreach($array as $key => $val){
    list($before,$after) = split("~",$val);
    $input = preg_replace($before,$after,$input);
  }
}

/* float: Some decimal value */

$allowedBadWordsPercent = 0.30;
$numberOfWords = str_word_count($textOfWebpage);
$numberOfBadWords = 0;
str_ireplace($badWords, '', $sourceOfWebpage, $numberOfBadWords);

if ($numberOfBadWords != 0) {
    $badWordsPercent = $numberOfWords / $numberOfBadWords;
} else {
    $badWordsPercent = 0;
}

if ($badWordsPercent > $allowedBadWordsPercent) {
    echo 'This is a naughty webpage';
}

【问题讨论】：

标签： php

【解决方案1】：

这是我要做什么的粗略想法。您可能会争辩说，将 str_ireplace() 纯粹用于计数是不正当的。我不确定是否有更多方向功能而不破坏正则表达式。

/* string: Obtained by CURL or similar */
$sourceOfWebpage;

$textOfWebpage = strip_tags($sourceOfWebpage);

/* array: Obtained by your filter.txt file */
$badWords;

/* float: Some decimal value */
$allowedBadWordsPercent = 0.30;

$numberOfWords = str_word_count($textOfWebpage);
$numberOfBadWords = 0;

str_ireplace($badWords, '', $sourceOfWebpage, $numberOfBadWords);

if ($numberOfBadWords != 0) {
    $badWordsPercent = $numberOfWords / $numberOfBadWords;
} else {
    $badWordsPercent = 0;
}

if ($badWordsPercent > $allowedBadWordsPercent) {
    echo 'This is a naughty webpage';
}

【讨论】：