在 MySQL 中获取 1054 未知列错误

Question

运行以下查询时，我收到 1054 错误，指出字段列表中的未知列是“rct.trial_id”。但据我所知，我的语法是正确的。任何帮助将不胜感激！

select 
r.id,
rv.segment_cytoband,
rv.variant_category,
rv.gene,
rv.variant,
ra.sensitive_tier1,
ra.contraindicated_tier1,
ra.sensitive_tier2,
ra.contraindicated_tier2,
rv.cdna,
rv.type as 'Variant Type',
r.last_published,
r.status,
spm.property_name,
sp.property_value as 'oncotreeCode',
r.tumor_cellularity,
s.lims_sample_id,
sr.sample_run_lims_id,
count(distinct rct.trial_id) as 'No. of Trials 1',
count(distinct ract.trial_id) as 'No. of Trials 2'
from report r
LEFT JOIN report_variants rv ON r.id = rv.report_id
LEFT JOIN report_assays ra ON r.id = ra.report_id
LEFT JOIN report_samples rs ON r.id = rs.report_id
LEFT JOIN sample_run sr ON rs.sample_run_id = sr.id
LEFT JOIN sample s ON sr.sample_id = s.id
LEFT JOIN run rn ON sr.run_id = rn.id
LEFT JOIN sample_properties_master spm ON rn.run_combination_id = spm.run_combination_id
LEFT JOIN sample_properties sp ON sr.sample_id = sp.sample_id
LEFT JOIN 
    (select rv.report_id, count(distinct rct.trial_id) from report_clinical_trials rct
        INNER JOIN report_variants rv on rv.id = rct.report_variant_id) as rcttrial ON rv.id = rct.report_variant_id
LEFT JOIN
    (select ra.report_id, count(distinct ract.trial_id) from report_assays_clinical_trials ract
        INNER JOIN report_assays ra on ra.id = ract.report_assay_id) as racttrial ON ra.id = ract.report_assay_id
where r.status = 'REPORT EXPORTED' 
having spm.property_name like 'oncotreeCode';

Answer 1

select 
r.id,
rv.segment_cytoband,
rv.variant_category,
rv.gene,
rv.variant,
ra.sensitive_tier1,
ra.contraindicated_tier1,
ra.sensitive_tier2,
ra.contraindicated_tier2,
rv.cdna,
rv.type as 'Variant Type',
r.last_published,
r.status,
spm.property_name,
sp.property_value as 'oncotreeCode',
r.tumor_cellularity,
s.lims_sample_id,
sr.sample_run_lims_id,
rcttrial.count as 'No. of Trials 1',
racttrial.count as 'No. of Trials 2'
from report r
LEFT JOIN report_variants rv ON r.id = rv.report_id
LEFT JOIN report_assays ra ON r.id = ra.report_id
LEFT JOIN report_samples rs ON r.id = rs.report_id
LEFT JOIN sample_run sr ON rs.sample_run_id = sr.id
LEFT JOIN sample s ON sr.sample_id = s.id
LEFT JOIN run rn ON sr.run_id = rn.id
LEFT JOIN sample_properties_master spm ON rn.run_combination_id = spm.run_combination_id
LEFT JOIN sample_properties sp ON sr.sample_id = sp.sample_id
LEFT JOIN 
    (select rv.report_id, count(distinct rct.trial_id) AS count from report_clinical_trials rct
        INNER JOIN report_variants rv on rv.id = rct.report_variant_id) as rcttrial ON r.id = rcttrial.report_id
LEFT JOIN
    (select ra.report_id, count(distinct ract.trial_id) AS count from report_assays_clinical_trials ract
        INNER JOIN report_assays ra on ra.id = ract.report_assay_id) as racttrial ON r.id = racttrial.report_id
where r.status = 'REPORT EXPORTED' 
having spm.property_name like 'oncotreeCode';    

Answer 2

您无法从主查询访问子查询中的表。

您需要在子查询中为count(distinct rct.trial_id) 提供别名，然后在主查询中使用该别名。 ract.trial_id 也是如此。

select 
    r.id,
    rv.segment_cytoband,
    rv.variant_category,
    rv.gene,
    rv.variant,
    ra.sensitive_tier1,
    ra.contraindicated_tier1,
    ra.sensitive_tier2,
    ra.contraindicated_tier2,
    rv.cdna,
    rv.type as 'Variant Type',
    r.last_published,
    r.status,
    spm.property_name,
    sp.property_value as 'oncotreeCode',
    r.tumor_cellularity,
    s.lims_sample_id,
    sr.sample_run_lims_id,
    rcttrial.count as 'No. of Trials 1',
    racttrial.count as 'No. of Trials 2'
from report r
LEFT JOIN report_variants rv ON r.id = rv.report_id
LEFT JOIN report_assays ra ON r.id = ra.report_id
LEFT JOIN report_samples rs ON r.id = rs.report_id
LEFT JOIN sample_run sr ON rs.sample_run_id = sr.id
LEFT JOIN sample s ON sr.sample_id = s.id
LEFT JOIN run rn ON sr.run_id = rn.id
LEFT JOIN sample_properties_master spm ON rn.run_combination_id = spm.run_combination_id
LEFT JOIN sample_properties sp ON sr.sample_id = sp.sample_id
LEFT JOIN 
    (select rv.report_id, count(distinct rct.trial_id) AS count from report_clinical_trials rct
        INNER JOIN report_variants rv on rv.id = rct.report_variant_id) as rcttrial ON rv.id = rct.report_variant_id
LEFT JOIN
    (select ra.report_id, count(distinct ract.trial_id) AS count from report_assays_clinical_trials ract
        INNER JOIN report_assays ra on ra.id = ract.report_assay_id) as racttrial ON ra.id = ract.report_assay_id
where r.status = 'REPORT EXPORTED' 
having spm.property_name like 'oncotreeCode';