如何提示用户打开位置服务，即转到设置→隐私→位置服务

Question

以下代码不再起作用，我们该怎么办

[[UIApplication sharedApplication] openURL:[NSURL URLWithString: @"prefs:root=LOCATION_SERVICES"]];

以下适用于转到设置→您的应用程序→位置，但我想访问转到设置→隐私→位置服务

        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

我遇到了与以下问题相同的问题

Open Settings app from another app programmatically in iPhone

Answer 1

如果用户不开启定位服务，我会使用此代码

 - (void)locationManager:(CLLocationManager *)manager
   didFailWithError:(NSError *)error {
     if ([[error domain] isEqualToString: kCLErrorDomain] && [error code] == kCLErrorDenied) {
       // The user denied your app access to location information.

       UIAlertView* alert=[[UIAlertView alloc] initWithTitle:@"This app does not have access to Location" message:@"You can enable access in Settings" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:@"Settings", nil];
       alert.delegate = self;
       [alert show];
     }


    NSLog(@"%@", error.description);
}

并在此代码中处理UIAlertView 中的Settings 按钮：

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
   NSLog(@"buttonIndex:%d",buttonIndex);

   if (buttonIndex == 1) {
       [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
   }
}