如何在 Json Parser android 中设置请求超时答案

【问题标题】：how to set request time out in Json Parser android如何在 Json Parser android 中设置请求超时
【发布时间】：2014-01-06 07:43:08
【问题描述】：

我创建了以下从服务器获取 json 的函数：

public class JSONParser {

static InputStream is = null;
static JSONObject jObj = null;
static String json = "";

// constructor
public JSONParser() {
}

public JSONObject getJSONFromUrl(String url) {

    // Making HTTP request
    try {
        // defaultHttpClient
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();           

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}

}

当用户连接不良时，它只是加载而不给出任何通知，我的问题是：当请求超时或连接不良时，我该如何添加诸如吐司？

【问题讨论】：

显示你的httprequest代码..
@segi 我只用这段代码来解析我的 json

标签： java android timeout httpresponse

【解决方案1】：

我知道，已经很久了，但我想帮忙，让我们尝试添加这个：

    HttpParams httpParameters = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(httpParameters, 10000);
    HttpConnectionParams.setSoTimeout(httpParameters, 10000);
    DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);

在您的代码中，这将是：

 try {
         HttpParams httpParameters = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(httpParameters, 10000);
    HttpConnectionParams.setSoTimeout(httpParameters, 10000);
        DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
        HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();           
} catch(ConnectTimeoutException e){
    Log.e("Timeout Exception: ", e.toString());
} catch(SocketTimeoutException ste){    
    Log.e("Timeout Exception: ", ste.toString());
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

为了显示消息请求超时，如果结果为空或为空，您可以在onPostExecute() 上添加警报消息等。

【讨论】：

这就是我需要在我的代码中实现它，非常感谢！

【解决方案2】：

首先设置 HttpRequestTimeOut 如下所示，然后将此逻辑添加到 try 和 catch 中，并在请求超时失败时将 toast 消息添加到 catch 块中，它会向您显示 toast 消息。

url = new URI(s.replace(" ", "%20"));

        Log.e("my webservice", "My webservice : " + url);

        HttpGet httpget = new HttpGet(url);
        HttpResponse httpResponse = null;

        HttpParams httpParameters = new BasicHttpParams();
        // Set the timeout in milliseconds until a connection is
        // established.
        // The default value is zero, that means the timeout is not used.
        int timeoutConnection = 3000;
        HttpConnectionParams.setConnectionTimeout(httpParameters,
                timeoutConnection);
        // Set the default socket timeout (SO_TIMEOUT)
        // in milliseconds which is the timeout for waiting for data.
        int timeoutSocket = 5000;
        HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

        DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);

        // Execute HTTP Post Request
        httpResponse = httpClient.execute(httpget);

【讨论】：