【发布时间】:2015-08-05 06:02:00
【问题描述】:
大家好,我一直在努力解决这个问题,但我无法解决它。任何人都可以帮我解决这个问题吗?我很困惑,有人可以帮助我如何修复代码吗?抱歉,我无法上传图片。
SELECT Employee.EmpName, Employee.Age
FROM Employee
WHERE Employee.Age < (SELECT COUNT(Employee.EmployeeID)
FROM Employee, Department
WHERE Department.ManagerID = Employee.EmployeeID
GROUP BY Employee.EmployeeID
HAVING COUNT(Employee.EmployeeID) >= 2)
//(问题)找到管理多个部门的最年轻的经理。查询返回经理的姓名和年龄。
架构
Employee(EmployeeID:Integer, EmpName: String, Age: Integer, Salary: Real)
Department(DeptID: Integer, DeptName:String, Budget: Real, ManagerID: Integer)
Works(EmployeeID:Integer, DeptID: Integer, Percent_Time: Integer)
【问题讨论】:
标签: mysql sql-server sqlite