从对象数组中过滤唯一值[重复]

Question

如何使用 Array.filter() 返回唯一的 id 和 name ？

我的方案与我研究过的解决方案略有不同，因为我有一组对象。我找到的每个示例都包含一个由单个值组成的平面数组。

data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];

var unique = data.filter(
function (x, i) {
   return data[i].id.indexOf(x.id) === i
});

提前致谢。

Answer 1

我认为forEach() 更能实现您的目标：

var data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];
var resArr = [];
data.forEach(function(item){
  var i = resArr.findIndex(x => x.name == item.name);
  if(i <= -1){
    resArr.push({id: item.id, name: item.name});
  }
});
console.log(resArr);

如果你真的想用filter()试试下面的方法：

var data=[
{id: 555, name: "Sales", person: "Jordan" },
{id: 555, name: "Sales", person: "Bob" },
{id: 555, name: "Sales", person: "John" },
{id: 777, name: "Accounts Payable", person: "Rhoda" },
{id: 777, name: "Accounts Payable", person: "Harry" },
{id: 888, name: "IT", person: "Joe" },
{id: 888, name: "IT", person: "Jake" },
];
var resArr = [];
data.filter(function(item){
  var i = resArr.findIndex(x => x.name == item.name);
  if(i <= -1){
    resArr.push({id: item.id, name: item.name});
  }
  return null;
});
console.log(resArr);