【发布时间】:2012-06-12 03:59:05
【问题描述】:
我需要生成一个 PHP 页面,该页面显示存储在数组中的所有详细信息(来自 MySQL 请求),以显示每个类似行项目的计数/摘要的方式。
以下是从 SQL 查询中收集的示例数据集(已按工作组、ProductCode 进行排序):
+----+-------------+-------------+-----------+-----------+
| ID | ProductCode | Description | Workgroup | Status |
+----+-------------+-------------+-----------+-----------+
| 2 | A123 | Coke | Finance | Ordered |
| 4 | A123 | Coke | Finance | Rejected |
| 1 | A123 | Coke | Finance | Rejected |
| 6 | B111 | Pepsi | Finance | Ordered |
| 5 | B111 | Pepsi | Finance | Rejected |
| 8 | B111 | Pepsi | Finance | Rejected |
| 10 | B112 | Fanta | Finance | Ordered |
| 42 | A123 | Coke | Management| Ordered |
| 16 | A123 | Coke | Management| Ordered |
| 11 | B112 | Fanta | Management| Rejected |
+----+-------------+-------------+-----------+-----------+
这些详细信息已存储在 PHP 数组中,如下所示:
Array
(
[0] => Array
(
[ID] => 2
[ProductCode] => A123
[Description] => Coke
[Workgroup] => Finance
[Status] => Ordered
)
[1] => Array
(
[ID] => 4
[ProductCode] => A123
[Description] => Coke
[Workgroup] => Finance
[Status] => Rejected
)
...etc
)
我需要的是在由 WorkGroup 分隔的多个表格中吐出数据,每个产品有一个汇总行,下面列出每个单独的行项目(它不需要是一个 html 表格,只是一些 HTML 结构能够表示行项目)
从我展示的 10 个示例条目中,它需要输出以下内容:
+--------------------------------------------------------+
| FINANCE TEAM |
+----+-------------+-------------+-----------+-----------+
| Coke Total: 3 Ordered: 1 Rejected: 2 |
+----+-------------+-------------+-----------+-----------+
| 2 | A123 | Coke | Finance | Ordered |
| 4 | A123 | Coke | Finance | Rejected |
| 1 | A123 | Coke | Finance | Rejected |
+----+-------------+-------------+-----------+-----------+
| Pepsi Total: 3 Ordered: 1 Rejected: 2 |
+----+-------------+-------------+-----------+-----------+
| 6 | B111 | Pepsi | Finance | Ordered |
| 5 | B111 | Pepsi | Finance | Rejected |
| 8 | B111 | Pepsi | Finance | Rejected |
+----+-------------+-------------+-----------+-----------+
| Fanta Total: 1 Ordered: 1 Rejected: 0 |
+----+-------------+-------------+-----------+-----------+
| 10 | B112 | Fanta | Finance | Ordered |
+----+-------------+-------------+-----------+-----------+
+--------------------------------------------------------+
| MANAGEMENT TEAM |
+----+-------------+-------------+-----------+-----------+
| Coke Total: 2 Ordered: 2 Rejected: 0 |
+----+-------------+-------------+-----------+-----------+
| 42 | A123 | Coke | Management| Ordered |
| 16 | A123 | Coke | Management| Ordered |
+----+-------------+-------------+-----------+-----------+
| Fanta Total: 1 Ordered: 0 Rejected: 1 |
+----+-------------+-------------+-----------+-----------+
| 11 | B112 | Fanta | Management| Rejected |
+----+-------------+-------------+-----------+-----------+
如果我的要求不够清楚,我可以进一步详细说明。
任何帮助将不胜感激。
提前致谢。
【问题讨论】:
-
当您以“我有...并且我需要...”开始发帖时,您可能应该评估您是否编写了任何代码来尝试解决您的问题。
-
抱歉,如果您认为我过于前卫。我试图解决我的问题,但没有一个值得发布,因为它完全是垃圾。正如我所说:“任何帮助都将不胜感激。”
-
完全和彻底的垃圾比没有更有用。如果你有什么问题,我们可以指出你哪里出了问题或者你可以在哪里做得更好。
标签: php mysql arrays foreach while-loop