【发布时间】:2015-04-06 06:26:51
【问题描述】:
我有代码
$hasil = "INSERT INTO pendaftaran VALUES ('$no_ai','$tgl_daftar','$kode_dokter','$kode_pasien','$petugas_jaga','$bayar','$status_ambil','$catatan')";
$sql = mysql_query($hasil);
foreach($_POST['cek'] as $selected){
foreach($_POST['cek'] as $selek){
$res = mysql_query("SELECT kode_cek FROM master_cek where kode_item='$selected'");
while($koko=mysql_fetch_array($res)){
print_r($koko);
$result = "INSERT INTO detail_daftar VALUES ('',$no_ai','$res','0','','','$selected')";
$sql = mysql_query($result);
print_r($result);
}
}
}
结果是..
Resource id #5 INSERT INTO detail_daftar VALUES ('',20150206015','Resource id #5','0','','','1011')Resource id #5INSERT INTO detail_daftar VALUES ('',20150206015','Resource id #5','0','','','1011')Resource id #5INSERT INTO detail_daftar VALUES ('',20150206015','Resource id #5','0','','','1011')
我对资源 ID 很困惑。请帮帮我谢谢:)
【问题讨论】:
-
您要打印什么?
-
你确定你没有在做
print_r($res);? -
能否请您添加 $_POST 来自的 html 代码?
-
html $_POST 来自