【发布时间】:2016-07-29 06:46:16
【问题描述】:
来自数据库的结果
(
[ID] => 3167
[数据ID] => 1
[数据] => P01273
[小时] => 1
[月] => 1
)
(
[ID] => 3168
[数据ID] => 1
[数据] => P01273
[小时] => 1
[月] => 2
)
(
[ID] => 3191
[数据ID] => 2
[数据] => P01273
[小时] => 10
[月] => 1
)
(
[ID] => 3196
[数据ID] => 2
[数据] => P01273
[小时] => 10
[月] => 2
)
(
[ID] => 3189
[数据ID] => 2
[数据] => P00428
[小时] => 22
[月] => 2
)
(
[ID] => 3189
[数据ID] => 2
[数据] => P004299
[小时] => 22
[月] => 2
)
如果月份和数据相等,则计算小时的总和
需要输出
(
[ID] => 3167
[数据ID] => 1
[数据] => P01273
[小时] => 11(加 1+11)
[月] => 1
)
(
[ID] => 3168
[数据ID] => 1
[数据] => P01273
[小时] => 11(加 1+11)
[月] => 2
)
(
[ID] => 3189
[数据ID] => 2
[数据] => P00428
[小时] => 22
[月] => 2
)
(
[ID] => 3189
[数据ID] => 2
[数据] => P004299
[小时] => 22
[月] => 2
)
【问题讨论】:
-
无法理解您的问题
-
第一个 id 中的 sum 是如何产生的
-
我建议您将问题陈述更改为:合并“数据”和“月份”相同的数组元素,同时将小时数相加。查看下面的解决方案