【发布时间】:2015-09-08 07:37:48
【问题描述】:
我有带有复合主键的表。
Server(key=ServerId)
ServerId|Name
1 |server1
2 |server2
ParentObj(key=ServerId+Code)
ServerId|Code |Title
1 |code1|value1
1 |code2|value2
2 |code1|Value2b
ChildObj(key=ServerId+Code+Name)
ServerId|Code |Name |Value
1 |code1|prop1|val1
1 |code1|prop2|val2
1 |code2|prop1|val1b
2 |code1|prop3|val3
这是我拥有的 Java bean。
@Entity @Table(name="ParentObj") @Access(AccessType.FIELD)
@IdClass(value=ParentObj.PK.class)
@XmlAccessorType(XmlAccessType.PUBLIC_MEMBER)
@XmlRootElement
public class ParentObj {
@Id private long serverId;
@Id private String code;
private String title;
public long getServerId() { return serverId; }
public String getCode() { return code; }
public String getTitle() { return title; }
public static class PK implements Serializable {
private static final long serialVersionUID = 1L;
private long serverId;
private String code;
public long getServerId() { return serverId; }
public void setServerId(long id) { serverId=id; }
public String getCode() { return code; }
public void setCode(String code) { this.code=code; }
}
}
@Entity @Table(name="ChildObj") @Access(AccessType.FIELD)
@IdClass(value=ChildObj.PK.class)
@XmlAccessorType(XmlAccessType.PUBLIC_MEMBER)
@XmlRootElement
public class ChildObj {
@Id private long serverId;
@Id private String code;
@Id private String name;
private String value;
// public getter+setters for each field
public static class PK implements Serializable {
private static final long serialVersionUID = 1L;
private long serverId;
private String code;
private String name;
public long getServerId() { return serverId; }
public void setServerId(long id) { serverId=id; }
public String getCode() { return code; }
public void setCode(String code) { this.code=code; }
public String getName() { return name; }
public void setName(String name) { this.name=name; }
}
}
我一直在尝试“一切”来创建 OneToMany 映射(ParentObj->ChildObj),但似乎没有任何效果。我不需要 ManyToOne(ParentObj
这是一个旧数据库,因此我无法插入 auto_increment 标识列或在父子节点之间创建额外的连接表。
这个注释在概念上是我想要的,但 OpenJPA2.x 库不接受多个连接列。
// from parent to zero or more childs
@OneToMany(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="server_id", referencedColumnName="server_id"),
@JoinColumn(name="code", referencedColumnName="code")
})
private List<ChildObj> properties;
编辑、回答 OneToMany、ManyToOne 和 EmbeddedId 注释有效。我只尝试阅读现有的行,但现在还可以。后来我尝试更新+插入+删除任务。
public class ParentObj {
@EmbeddedId ParentObj.PK pk;
@OneToMany(fetch=FetchType.LAZY, cascade=CascadeType.ALL, mappedBy="parent", orphanRemoval=true)
private List<ChildObj> childs;
public PK getPK() { return pk; }
public void setPK(PK pk) { this.pk=pk; }
public List<ChildObj> getChilds() { return childs; }
...
@Embeddable @Access(AccessType.FIELD)
public static class PK implements Serializable {
private static final long serialVersionUID = 1L;
@Column(nullable=false) private long serverId;
@Column(nullable=false) private String code;
..getters+setters+hashCode+equals functions
}
}
public class ChildObj {
@EmbeddedId ChildObj.PK pk;
@ManyToOne(fetch=FetchType.LAZY, cascade=CascadeType.PERSIST, optional=false)
@JoinColumns({
@JoinColumn(name="serverid", referencedColumnName="serverid", nullable=false),
@JoinColumn(name="code", referencedColumnName="code", nullable=false)
})
private ParentObj parent;
public PK getPK() { return pk; }
public void setPK(PK pk) { this.pk=pk; }
public long getServerId() { return pk.getServerId(); }
public String getCode() { return pk.getCode(); }
public String getName() { return pk.getName(); }
...
@Embeddable @Access(AccessType.FIELD)
public static class PK implements Serializable {
private static final long serialVersionUID = 1L;
@Column(nullable=false) private long serverId;
@Column(nullable=false) private String code;
@Column(nullable=false) private String name;
..getters+setters+hashCode+equals functions
}
}
【问题讨论】:
-
最简单的方法是创建一个从
ChildObj到ParentObj的@ManyToOne关联,然后将mappedBy用于ParentObj中的@oneToMany。另外,我建议您使用@EmbeddedId和@EmbeddablePK 类。 -
它可以工作,并且 EmbeddedId 重复的代码更少。谢谢。如果您发布答案,我可以正确接受。
-
我已经发布了一个答案,但请注意您的
@Embeddable类应该是一个单独的(而不是内部)类 - 请参阅我的答案。