codeigniter 分页中的索引限制答案

【问题标题】：Index limit in codeigniter paginationcodeigniter 分页中的索引限制
【发布时间】：2016-02-19 15:42:39
【问题描述】：

抱歉，我希望创建表分页连接两个表我尝试创建它，当我单击“下一步”时，会出现这样的错误。

我在控制器中的代码

public function index()
{
    $this->load->model('mymodel');
    $this->load->library('pagination');
    $config['base_url'] = base_url().'index.php/admin/page/index/';
    $config['total_rows'] = $this->mymodel->tampil_data()->num_rows();
    $config['per_page'] = 10; 
    $this->pagination->initialize($config); 
    $data['paging']     =$this->pagination->create_links();
    $halaman            =  $this->uri->segment(3);
    $halaman            =$halaman==''?0:$halaman;
    $data['record']     =    $this->mymodel->tampil_data_paging($halaman,$config['per_page']);
    $this->template->load('template','view',$data);
}

和我的模型

    function tampil_data()
    {
        $query= "SELECT b.requestorname,b.checkin,b.checkout,b.company,b.email,b.contactnumber,b.purpose,
        kb.name,kb.checkinvisitor,kb.checkoutvisitor,kb.companyvisitor,kb.position,kb.contactnumbervisitor
                FROM messrequestor as b,messvisitor as kb
                WHERE b.idrequestor=kb.idrequestor";
        return $this->db->query($query);
    }

        function tampil_data_paging($halaman,$batas)
    {
        $query= "SELECT b.requestorname,b.checkin,b.checkout,b.company,b.email,b.contactnumber,b.purpose,
        kb.name,kb.checkinvisitor,kb.checkoutvisitor,kb.companyvisitor,kb.position,kb.contactnumbervisitor
                FROM messrequestor as b,messvisitor as kb
                WHERE b.idrequestor=kb.idrequestor limit $halaman,$batas";
        return $this->db->query($query);
    }

如何解决？

谢谢

【问题讨论】：

标签： php mysql codeigniter pagination

【解决方案1】：

public function index()
{
    $this->load->model('mymodel');
    $this->load->library('pagination');
    $config['base_url'] = base_url().'index.php/admin/page/index/';
    $config['total_rows'] = $this->mymodel->tampil_data()->num_rows();
    $config['per_page'] = 10; 
    $this->pagination->initialize($config); 
    $data['paging']     =$this->pagination->create_links();
    $halaman            =  $this->uri->segment(3);
    $halaman            =$halaman==''?0:$halaman;
    $data['record']     =    $this->mymodel->tampil_data_paging($halaman,$config['per_page']);
    $this->template->load('template','view',$data);
}

在此控制器中，您将段检索为“索引”，因此将其放置在您的 sql 中，您需要获取其他段

【讨论】：

【解决方案2】：

$config['base_url'] = base_url().'index.php/admin/page/index/';
//then you use this
$halaman =  $this->uri->segment(3);
$halaman =$halaman==''?0:$halaman;

这是将段检索为“索引”，因此将其放置在您的 sql 中，这就是错误所在。如果实际值在之后，则您需要获取其他段，即 4

$query= "SELECT b.requestorname,b.checkin,b.checkout,b.company,b.email,b.contactnumber,b.purpose,
    kb.name,kb.checkinvisitor,kb.checkoutvisitor,kb.companyvisitor,kb.position,kb.contactnumbervisitor
            FROM messrequestor as b,messvisitor as kb
            WHERE b.idrequestor=kb.idrequestor limit $halaman,$batas

【讨论】：