Laravel if 条件查询

Question

我有四个输入字段： 像这样

$cou = Input::get('activitycou');
$type = Input::get('activitytype');
$Des = Input::get('activityDes');

我执行以下操作：

If ($type!=null){
$query=Activity::where('id', $type)->get();   
}
If ($Des!=null){
$query=Activity::where('des_id', $Des)->get();   
}

等 但是问题是 $query 显示不正确，有人可以提出解决方案吗？

Answer 1

如果您想获得结合所有选项的结果，您可以执行以下操作（使用union 方法，您可以组合多个查询）：

If ($type!=null && $Des!=null && $cou!=null){
   $query1 = Activity::where('id', $type);   
   $query2 = Activity::where('des_id', $Des);
   $query3 = Activity::where('des_id', $cou);
   $allQueries = $query1->union($query2)->union($query3)->get();
 } elseif ($type!=null && $Des!=null){
   $query1 = Activity::where('id', $type);   
   $query2 = Activity::where('des_id', $Des);
   $allQueries = $query1->union($query2)->get();
 } elseif ($type!=null && $cou!=null){
   $query1 = Activity::where('id', $type);   
   $query2 = Activity::where('des_id', $cou);
   $allQueries = $query1->union($query2)->get();
 } elseif ($type!=null && $cou!=null){
   $query1 = Activity::where('id', $type);   
   $query2 = Activity::where('des_id', $Des);
   $allQueries = $query1->union($query2)->get();
 } elseif ($Des!=null && $cou!=null){
   $query1 = Activity::where('id', $cou);   
   $query2 = Activity::where('des_id', $Des);
   $allQueries = $query1->union($query2)->get();
 } elseif ($type!=null){
   $query1 = Activity::where('id', $type)->get();
 } elseif ($Des!=null){
   $query1 = Activity::where('id', $Des)->get();
 } elseif ($cou!=null){
   $query1 = Activity::where('id', $cou)->get();
 }