从表中获取最高值

Question

我试图只显示第一行，在 MYSQL 中的示例是：

ORDER BY foo DESC LIMIT 1; 

我相信 oracle 不使用LIMIT 子句。我试过ROWNUM = 1，但它似乎不起作用。这是显示第一行的正确方式吗？

select customer_name, 
       MAX(balance) as "Highest Depositor Value"
  from depositor
 inner join account
    on depositor.account_number = account.account_number
 group by customer_name, balance
 order by balance
 where rownum = 1;


ERROR at line 4:
ORA-00933: SQL command not properly ended

我得到了答案！谢谢

select customer_name,max(balance) as "Highest Depositor Value"
 from depositor
 inner join account
    on depositor.account_number = account.account_number
 group by customer_name, balance order by balance desc
 fetch first 1 rows only;


CUSTOMER_NAME   Highest Depositor Value
 --------------- -----------------------
 Lindsay                          100000

Answer 1

我在这里找到了很好解释的答案。

How do I limit the number of rows returned by an Oracle query after ordering?

  select customer_name,max(balance) as "Highest Depositor Value"
2  from depositor
3  inner join account on depositor.account_number = account.account_number
4  group by customer_name, balance order by balance desc
5  fetch first 1 rows only;
CUSTOMER_NAME   Highest Depositor Value
 --------------- -----------------------
 Lindsay                          100000

Answer 2

删除这部分：

order by balance where rownum = 1

你所拥有的应该可以工作..

MAX 会给你最大的......你不需要告诉它有多少行，MAX 只会给出 1 个最大值。

[编辑] 如果您只想要 1 个最大值，则需要按 .. 删除组/订单，并从选择中删除“客户名称”：

  select MAX(balance) as "Highest Depositor Value"
  from depositor
  inner join account on depositor.account_number = account.account_number;

[/编辑]