JavaScript“this”不适用于 HTML 元素

Question

我想用img 元素在div 中显示信息，我通过php 访问数据库。我将onmouseover event 与每个元素相关联，并将this 和一些参数作为参数传递，但是当我将鼠标悬停在图像上时，div 显示在浏览器的左上角并且不显示在图像旁边。

我也尝试过删除this，结果还是一样。

图像元素的代码

         $row = mysqli_fetch_array($result);

          $firstname = $row['firstname'];

          $lastname = $row['lastname'];

          $image =    $row['image'];

          $phone =    $row['phone'];

          $email =    $row['email'];

     $realtorData = $firstname.'|'.$lastname.'|'.$phone.'|'.$email.'|';
echo "<img src='/../../Realtors/$image'onmouseover='showRealtorInfo(this,\"".$realtorData."\" );' onmouseout='hideRealtorInfo();'>";

javaScript 代码

  function showRealtorInfo(element, realtorInfo)
{
    var realtorArray = realtorInfo.split('|');

    var firstname = realtorArray[0];
    var lastname  = realtorArray[1];
    var phone     = realtorArray[2];
    var email     = realtorArray[3];

    var realtorInfoDiv = document.getElementById('realtorinfo');

    var myHTML  = "<p><b>" + firstname + " " + lastname + "</b><br /><br />";
        myHTML += "Phone: " + phone + "<br />";
        myHTML += "Email: " + email + "<br />";

    realtorInfoDiv.innerHTML = myHTML;

    x = element.offsetLeft;
    y = element.offsetTop;

    //alert(x);

    realtorInfoDiv.style.left = y + 100;
    realtorInfoDiv.style.top = x + 550;



    realtorInfoDiv.style.visibility = 'visible';


}

div元素的css代码

#realtorinfo{

position: absolute;
left: 10px;
top: 10px;
width: 200px;
height: 150px;
padding: 5px;
background-color: yellow;
visibility: hidden;
float: left;

} 

Answer 1

您在后续 LOC 中没有提到“px”。

realtorInfoDiv.style.left = y + 100;
realtorInfoDiv.style.top = x + 550;

这应该可行：

realtorInfoDiv.style.left = y + 100 + "px";
realtorInfoDiv.style.top = x + 550 + "px";