【发布时间】:2011-05-11 21:19:40
【问题描述】:
我只是想知道如何在 PHP 中回显一系列日期
理想情况下,我希望系统显示本周星期三到下周星期三
例如
17/11/10 到 24/11/10
谁能指出我正确的方向?
【问题讨论】:
我只是想知道如何在 PHP 中回显一系列日期
理想情况下,我希望系统显示本周星期三到下周星期三
例如
17/11/10 到 24/11/10
谁能指出我正确的方向?
【问题讨论】:
我在你的问题中没有提到 mysql,但如果你真的在谈论它:
select * from my_table where date_fld between '17/11/10' and '24/11/10'
【讨论】:
创建一个日期,并为其添加天数...
$m= date("m");
$de= date("d");
$y= date("Y");
for($i=0; $i<8; $i++){
echo date('d-m-y:D',mktime(0,0,0,$m,($de+$i),$y));
echo "<br>";
}
【讨论】:
$oBeginDate = new DateTime('last wednesday');
$oEndDate = new DateTime('next wednesday');
echo $oBeginDate->format('d/m/Y') . ' to ' . $oEndDate->format('d/m/Y');
【讨论】:
使用 strtotime
$now = '17/11/2010';
$next_week = date('d/m/Y', strtotime('+1 week', strtotime($now)));
【讨论】:
由于 MySQL 被标记...
SELECT now(),
case
when weekday(now()) = 3 then date_sub(now(), interval 1 day)
when weekday(now()) = 2 then curdate()
when weekday(now()) = 1 then date_add(now(), interval 1 day)
when weekday(now()) = 0 then date_add(now(), interval 2 day)
when weekday(now()) = 4 then date_sub(now(), interval 1 day)
when weekday(now()) = 5 then date_sub(now(), interval 2 day)
when weekday(now()) = 6 then date_sub(now(), interval 3 day)
end as current_wednesday,
case
when weekday(now()) = 3 then date_add(now(), interval 6 day)
when weekday(now()) = 2 then date_add(now(), interval 7 day)
when weekday(now()) = 1 then date_add(now(), interval 8 day)
when weekday(now()) = 0 then date_add(now(), interval 9 day)
when weekday(now()) = 4 then date_add(now(), interval 5 day)
when weekday(now()) = 5 then date_add(now(), interval 4 day)
when weekday(now()) = 6 then date_add(now(), interval 3 day)
end as next_wednesday
【讨论】: