【发布时间】:2017-02-07 10:07:22
【问题描述】:
【问题讨论】:
标签: join common-table-expression derived-table
【问题讨论】:
标签: join common-table-expression derived-table
SELECT t1.id,
t1.name
FROM emp_table t1
INNER JOIN -- the join will remove employees who do not have
( -- two phone numbers in phone_table
SELECT Id
FROM phone_table -- this query identifies all employees
GROUP BY Id -- having two phone numbers in phone_table
HAVING COUNT(*) = 2
) t2
ON t1.id = t2.Id
【讨论】: