如何将csv转换为xml，其中csv中的每一列=标签的xml属性答案

【问题标题】：How to convert csv into xml where each column in csv = xml attribute of tag如何将csv转换为xml，其中csv中的每一列=标签的xml属性
【发布时间】：2019-10-31 17:41:07
【问题描述】：

如何将 csv 转换为 xml，其中 csv 中的每一列都是通过 C# 的 xml 标签中的属性？让我告诉你我的意思：这是 CSV：

1;A;a;b;c;d;
2;B;e;f;g;h;

这是 Xml：

<section>
  <row code="1" s1="A">
    <col code="5">a</col>
    <col code="6">b</col>
    <col code="7">c</col>
    <col code="8">d</col>
  </row>
  <row code="2" s1="B">
    <col code="5">e</col>
    <col code="6">f</col>
    <col code="7">g</col>
    <col code="8">h</col>
  </row>
</section>

其中“行代码”= 第一列，“s1”=2nd，“col 代码=5”=3rd，“col 代码=6”=第 4 列 ets。这就是任务。

现在我有 xmlSchema 类，csv 类，但是我在映射 csv - xml 时遇到了一些问题。这是 XMLSchema.cs 的一部分：

public partial class reportSectionsSectionRowCol
{
    private string codeField;
    private string valueField;
    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string code
    {   get {return this.codeField;}
        set {this.codeField = value;}
    }
    [System.Xml.Serialization.XmlTextAttribute()]
    public string Value
    {
        get{return this.valueField;}
        set{this.valueField = value;}
    }
}

col - 具有属性代码和值的 XML 元素。

<row code="1" s1="A">
    <col code="5">a</col>
    <col code="6">b</col>
    <col code="7">c</col>
    <col code="8">d</col>
</row>

这是映射：

static void MappingCSVtoXML(report report, CSVData csvData)
        {
            if (csvData != null)
            {
                var col = new reportSectionsSectionRowCol[]{   new reportSectionsSectionRowCol(),
                                                               new reportSectionsSectionRowCol(),
                                                               new reportSectionsSectionRowCol(),
                                                               new reportSectionsSectionRowCol()};                


                var row = new reportSectionsSectionRow[2] { new reportSectionsSectionRow(), new reportSectionsSectionRow() };
                for (int i = 0; i < 2; i++)
                {
                    col[0].code = "5"; col[0].Value = csvData.rows[i].depreciationGroupNumber;
                    col[1].code = "6"; col[1].Value = csvData.rows[i].commissioningYear;
                    col[2].code = "7"; col[2].Value = csvData.rows[i].startYear;
                    col[3].code = "8"; col[3].Value = csvData.rows[i].ageAtLiquidation;


                    row[i].code = csvData.rows[i].okof.Substring(0, 3); // 1,2
                    row[i].col = col; // Reference type
                    row[i].s1 = csvData.rows[i].rowNumber; //A,B                               
                }

                report.sections = new reportSectionsSection[1]{new reportSectionsSection(){code = "1", row = row}};

            }
        }

问题在于 col 是引用类型，并且只记住最后一个值。总体结果是

<section>
  <row code="1" s1="A">
    <col code="5">e</col>
    <col code="6">f</col>
    <col code="7">g</col>
    <col code="8">h</col>
  </row>
  <row code="2" s1="B">
    <col code="5">e</col>
    <col code="6">f</col>
    <col code="7">g</col>
    <col code="8">h</col>
  </row>
</section>

我该如何解决？

【问题讨论】：

我会构建一些数据类来表示 CSV 数据和 XML 数据的结构。然后使用 filehelpers.net 之类的库导入 CSV 数据，将其映射到 XML 数据类并使用 XML 序列化器将其导出。
@MindSwipe 对我来说，没有理由赞成或反对，但这只是我的意见，拥有一个 POV 绝对没问题。我欢迎你的评论，为什么你不投票:o)
@SirRufo 请检查下面的答案
如果您想回答问题，您应该只发布一个答案。如果您想为问题提供更多信息，请编辑问题。
@SirRufo 好的，我做到了

标签： c# xml csv converters

【解决方案1】：

这是我的类结构的映射代码

static Section Map( IEnumerable<Csv1Data> source )
{
    return new Section
    {
        Rows = source
            .Select( e => new SectionRow
            {
                Code = e.Code,
                Value = e.S1,
                Columns = new List<SectionRowCol>
                {
                    new SectionRowCol{ Code = 5, Value = e.Col5, },
                    new SectionRowCol{ Code = 6, Value = e.Col6, },
                    new SectionRowCol{ Code = 7, Value = e.Col7, },
                    new SectionRowCol{ Code = 8, Value = e.Col8, },
                }
            } )
            .ToList(),
    };
}

简单的检查和用例

static void Main( string[] args )
{
    var source = new List<Csv1Data> {
        new Csv1Data { Code = 1, S1 = "A", Col5 = "a", Col6 = "b", Col7 = "c", Col8 = "d" },
        new Csv1Data { Code = 2, S1 = "B", Col5 = "a", Col6 = "b", Col7 = "c", Col8 = "d" },
    };

    var output = Map( source );

    XmlSerializer ser = new XmlSerializer( typeof( ExportModels.Xml1.Section ) );

    using ( var stream = new MemoryStream() )
    {
        using ( var writer = new StreamWriter( stream, Encoding.UTF8 ) )
        {
            ser.Serialize( writer, output );
        }

        var bytes = stream.ToArray();
        var str = Encoding.UTF8.GetString( bytes );
        Console.WriteLine( str );
    }
}

XML 数据类

// HINWEIS: Für den generierten Code ist möglicherweise mindestens .NET Framework 4.5 oder .NET Core/Standard 2.0 erforderlich.
/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute( "code" )]
[System.Xml.Serialization.XmlTypeAttribute( AnonymousType = true )]
[System.Xml.Serialization.XmlRootAttribute( Namespace = "", IsNullable = false, ElementName = "section" )]
public partial class Section
{

    private List<SectionRow> _rowField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute( "row" )]
    public List<SectionRow> Rows
    {
        get
        {
            return this._rowField;
        }
        set
        {
            this._rowField = value;
        }
    }
}

/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute( "code" )]
[System.Xml.Serialization.XmlTypeAttribute( AnonymousType = true )]
public partial class SectionRow
{

    private List<SectionRowCol> _columnsField;

    private int _codeField;

    private string _valueField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute( "col" )]
    public List<SectionRowCol> Columns
    {
        get
        {
            return this._columnsField;
        }
        set
        {
            this._columnsField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute( AttributeName = "code" )]
    public int Code
    {
        get
        {
            return this._codeField;
        }
        set
        {
            this._codeField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute( AttributeName = "s1" )]
    public string Value
    {
        get
        {
            return this._valueField;
        }
        set
        {
            this._valueField = value;
        }
    }
}

/// <remarks/>
[System.SerializableAttribute()]
[System.ComponentModel.DesignerCategoryAttribute( "code" )]
[System.Xml.Serialization.XmlTypeAttribute( AnonymousType = true )]
public partial class SectionRowCol
{

    private byte _codeField;

    private string _valueField;

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute( AttributeName = "code" )]
    public byte Code
    {
        get
        {
            return this._codeField;
        }
        set
        {
            this._codeField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlTextAttribute()]
    public string Value
    {
        get
        {
            return this._valueField;
        }
        set
        {
            this._valueField = value;
        }
    }
}

CSV 数据类

class Csv1Data
{
    public int Code { get; set; }
    public string S1 { get; set; }
    public string Col5 { get; set; }
    public string Col6 { get; set; }
    public string Col7 { get; set; }
    public string Col8 { get; set; }
}

【讨论】：