【发布时间】:2016-05-22 17:01:19
【问题描述】:
...表名是参数。我在这里找到了解决方案:unable to store return value from execute statement in mysql 但这对我不起作用。这是我的测试:
SET @v_sourceTableSize = 0;
SET @parameter_sourceTable = category;
SET @v_query = CONCAT("SELECT COUNT(*) INTO ",@v_sourceTableSize," FROM ",@parameter_sourceTable);
category 是我数据库中的一个表。当我运行它时,什么也没有发生。没有错误,什么都没有。有没有办法让它工作?从早上开始我就一直在寻找解决方案!
编辑
我在引号之间放置了“类别”,现在它正在工作,但是我的原始程序没有。请看:
DROP PROCEDURE IF EXISTS insert_categories;
DELIMITER $$
CREATE PROCEDURE insert_categories(
IN parameter_sourceTableIdColumnName INTEGER,
IN parameter_sourceTable VARCHAR(25),
IN parameter_sourceColumn VARCHAR(25),
IN parameter_destinationParentCategoryID INTEGER)
MODIFIES SQL DATA
BEGIN
DECLARE v_parameterSourceTable VARCHAR(25) DEFAULT "";
DECLARE v_sourceTableSize INTEGER;
DECLARE v_counter INTEGER DEFAULT 0;
DECLARE v_query VARCHAR(100) DEFAULT "";
DECLARE v_recordName VARCHAR(25) DEFAULT "";
SET v_parameterSourceTable = parameter_sourceTable;
SET v_query = CONCAT("SELECT COUNT(*) INTO ",v_sourceTableSize," FROM ",v_parameterSourceTable);
PREPARE stmt FROM v_query;
EXECUTE stmt;
SELECT v_sourceTableSize;
#SET v_sourceTableSize := (SELECT COUNT(*) FROM parameter_sourceTable);
SET v_sourceTableSize = v_sourceTableSize + 1;
WHILE v_counter < v_sourceTableSize DO
SET v_counter = v_counter + 1;
SET v_recordName = (SELECT parameter_sourceColumn
FROM v_parameterSourceTable
WHERE parameter_sourceTableIdColumnName = v_counter);
CALL insertCategory(v_recordName, parameter_destinationParentCategoryID);
END WHILE;
END $$
DELIMITER ;
我收到此错误:
1064 - 您的 SQL 语法有错误;查看与您的 MariaDB 服务器版本相对应的手册,了解在 'v_query; 附近使用的正确语法; 执行语句; 选择 v_sourceTableSize; 在第 17 行设置 v_sourceTa'
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标签: mysql prepared-statement mariadb concat