【发布时间】:2017-10-07 09:31:26
【问题描述】:
我正在努力将我的 SELECT all 语句结果传递给我的视图。我正在使用烧瓶和 MySQLdb。将我的所有结果从我的表格显示到我的 HTML 页面的正确语法是什么?我很想通过一个列表,但无法弄清楚它的语法。
HTML 调用 {{ session.qid }} 只是为了测试,没有任何显示。
这是我目前的python代码:
@app.route('/view_answered/', methods=['GET','POST'])
def view_answered():
error = ''
try:
if request.method == 'POST':
c, conn = connection()
clientcid = session['clientcid']
cursor.execute("SELECT * FROM tickets WHERE cid = 1 AND solved = 0")
results = cursor.fetchall()
x = 0
qid = []
difficulty = []
time_stamp = []
title = []
body = []
for row in results:
qid[x] = row[0]
difficulty[x] = row[3]
time_stamp[x] = row[4]
title[x] = row[6]
body[x] = row[7]
x = x + 1
conn.commit()
c.close()
conn.close()
gc.collect()
session['qid'] = qid
session['difficulty'] = difficulty
session['time_stamp'] = time_stamp
session['title'] = title
session['body'] = body
return redirect(url_for('view_answered'))
else:
error = "Something is aloof."
return render_template("view_answered.html")
except Exception as e:
return(str(e))
【问题讨论】:
标签: python flask mysql-python