【发布时间】:2012-01-03 21:28:16
【问题描述】:
我有以下:
Account --> Options
Account --> Profiles --> Options
这是模型
# models/account.rb
class Account < ActiveRecord::Base
has_many :accounts_has_options
has_many :options, :through => :accounts_has_options
has_many :accounts_has_profiles
has_many :profiles, :through => :accounts_has_profiles
end
# models/profile.rb
class Profile < ActiveRecord::Base
has_many :profiles_has_options
has_many :options, :through => :profiles_has_options
has_many :accounts_has_options
has_many :accounts, :through => :account_has_options
end
# models/option.rb
class Option < ActiveRecord::Base
has_many :accounts_has_options
has_many :accounts, :through => :accounts_has_options
has_many :profiles_has_options
has_many :profiles, :through => :profiles_has_options
end
我希望将所有选项与帐户关联,并通过配置文件关联所有选项,可能在虚拟属性中。
我在该问题中找到了一个示例: How do you concatenate two active record results to return a new result that can further be filtered? 但他们只关心两个模型,在我的例子中,我们在故事中有一个连接表。
任何想法,如何编写这样的虚拟属性?
【问题讨论】:
-
您是否尝试过该问题的建议?我看不出它不起作用的任何特殊原因。
标签: ruby-on-rails activerecord model