查找与汤姆·汉克斯在同一部电影中演出的所有演员答案

【问题标题】：Find all actors who played in the same movie as Tom Hanks查找与汤姆·汉克斯在同一部电影中演出的所有演员
【发布时间】：2017-07-04 19:02:32
【问题描述】：

我有一个 sql 语句的开头，我应该在其中找到与汤姆汉克斯在同一部电影中扮演过的所有演员。

select  a.name, m.title
from actor a 
inner join character c
inner join movie m

on a.id = c.actor_id
on c.movie_id = m.id

where a.name = 'Tom Hanks'

但是，这段代码只给了我汤姆汉克斯演过的所有电影的名字，而不是每个演员的名字。

表格是这样的

Actor:
  ID
  name

  Primary Key: ID      

Character:
  Actor_ID
  Movie_ID
  Character

  Primary Key: (actor_id, movie_id, character)
  Foreign Key: actor_id references actor(id)
  Foreign Key: movie_id references movie(id)

Movie:
  ID
  Title
  Year
  Mpaa_rating
  Audience_score
  Critics_score

  Primary Key: ID

我已经用不同的子查询和内部连接搞砸了一段时间，但似乎无法弄清楚我做错了什么。

【问题讨论】：

标签： sql subquery inner-join

【解决方案1】：

为简单起见分成子查询

-- get all actors that are in movies that tom hanks is in
SELECT  * 
FROM    actor 
WHERE   
    actor_id IN 
    (   -- get all actor ids that are in movies that tom hanks is in
        SELECT  actor_id 
        FROM    character 
        WHERE   
            movie_id IN 
            (   -- get all movies that tom hanks is in
                SELECT  movie_id 
                FROM    character
                WHERE   
                    actor_id IN 
                    (   -- get actor ids that equal tom hanks
                        SELECT id 
                        FROM actor 
                        WHERE name = 'Tom Hanks'
                    )
            )
    )

【讨论】：

【解决方案2】：

我之前犯了一个错误，需要一个“in”而不是“=” 你也应该试试这个：

Select a.name, m.title
From actor a, movie m, character c
Where a.id = c.actor_id
And m.id = c.movie_id
And m.id in ( select movie_id from character where actor_id = (select id from actor where name = 'the name'))

【讨论】：