使用其字段中的值更新 Oracle 表中的 XMLTYPE答案

【问题标题】：Update XMLTYPE in Oracle table with values from it's fields使用其字段中的值更新 Oracle 表中的 XMLTYPE
【发布时间】：2011-07-07 17:21:45
【问题描述】：

我在 Oracle 10gR2 中有一个现有表，我在其中添加了一个 XMLTYPE 列。现在，我需要用一个 XML 填充该字段，该 XML 由每行字段中的混合值组成，但我无法正确地获取语法。下面是为每一行生成所需 XML 的正确工作的 SELECT 语句：

SELECT XMLELEMENT("TBLOrigs",
  XMLELEMENT("TBLOrig", XMLATTRIBUTES(Field1 AS "Field1"),
  XMLFOREST(Field2 AS "Field2", Field3 AS "Field3", Field4 AS "Field4", Field5 AS "Field5"),
    XMLELEMENT("Dets",
    XMLFOREST(Field6, Field7 AS "Field7")))) AS XmlCol
  FROM TBLOrigin Orig1
WHERE Field1 <= 10

我正在尝试的更新是这样的，但它不起作用：

UPDATE TBLOrigin
SET AUXFIELD = (
  SELECT XMLELEMENT("TBLOrigs",
  XMLELEMENT("TBLOrig", XMLATTRIBUTES(Field1 AS "Field1"),
  XMLFOREST(Field2 AS "Field2", Field3 AS "Field3", Field4 AS "Field4", Field5 AS "Field5"),
    XMLELEMENT("Dets",
    XMLFOREST(Field6, Field7 AS "Field7")))) AS XmlCol
  FROM TBLOrigin Orig1
  WHERE Orig1.Field1 = Orig2.Field1
  AND Orig1.Field2 = Orig2.Field2
  AND Orig1.Field3 = Orig2.Field3
  AND Orig1.Field4 = Orig2.Field4
  AND Orig1.Field5 = Orig2.Field5)
FROM TBLOrigin Orig2
WHERE Field1 <= 10

我正在尝试使用从其字段生成的 XML 内容更新每一行。我不断收到以下错误：

Erro na Linha de Comando:13 Coluna:47
Relatório de Erro:
Erro de SQL: ORA-00933: SQL command not properly ended
00933. 00000 -  "SQL command not properly ended"
*Cause:    
*Action:

作为参考，下面是 Transact Sql 中的工作更新

UPDATE dbo.TBLOrigin
SET AuxInfo = (SELECT 
  Field1 as "@Field1",
  Field2 as "Field2", 
  Field3 as "Field3", 
  Field4 as "Field4", 
  Field5 as "Field5", 
  Field6 as "Dets/Field6", 
  Field7 as "Dets/Field7"
FROM dbo.TBLOrigin AS Orig1
WHERE Orig1.Field1 = Orig2.Field1
AND Orig1.Field2 = Orig2.Field2
AND Orig1.Field3 = Orig2.Field3
AND Orig1.Field4 = Orig2.Field4
AND Orig1.Field5 = Orig2.Field5
  FOR XML PATH('TBLOrig'), TYPE, ROOT('TBLOrigs'))
FROM dbo.TBLOrigin Orig2

非常感谢您的帮助

【问题讨论】：

标签： oracle ora-00933 xmltype

【解决方案1】：

Oracle 不执行 UPDATE...FROM

以下是否有效？

UPDATE TBLOrigin
SET AUXFIELD = 
       XMLELEMENT("TBLOrigs",
         XMLELEMENT("TBLOrig", XMLATTRIBUTES(Field1 AS "Field1"),
         XMLFOREST(Field2 AS "Field2", Field3 AS "Field3", 
                   Field4 AS "Field4", Field5 AS "Field5"),
         XMLELEMENT("Dets",
            XMLFOREST(Field6, Field7 AS "Field7")))) AS XmlCol
WHERE Field1 <= 10

如果没有，您可以发布表定义吗？

【讨论】：

是的……马上！比 TSQL 语法简单得多。非常感谢！