我猜你的查询结构本身有问题，因为它不仅仅是对distinct 的请求。
您的连接表，并为您拥有的每一行检索不同的值，您实际上只想为 KOTTAKKAL 和 KALPETTA 中的每一个提供一个。
请注意，在您的示例中，尽管添加了子句 distinct，但不会出现任何差异，因为您拥有的行 是不同的。在列平衡中，KOTTAKKAL 和 KALPETTA 的每个条目都有 341.00 和 394.00。
如果使用组，是的，您将丢失有关balance 的信息，因为group by 之后返回的结果只是分组的不同元素中的第一个（如果列具有多个值）。
您要么必须确定您想要的结果，要么应对在balance 列上进行其他计算。
我猜结果，你愿意做的正确加入是这样的：
SELECT DISTINCT E.`region_id`,a0.status0,a1.status1,k.discount,k.branches
,k.branch_names, k.balance,TCLRS.telecallers,FSE.fses
FROM tbl_insurance_excel E
LEFT OUTER JOIN (SELECT E2.region_id, count(`id`) AS status1
FROM tbl_insurance_excel E2 LEFT JOIN tbl_recipt_general_details ON id=insurance_excel_id
JOIN tbl_branches ON policy_closed_branch= branch_id
WHERE E2.`row_status` =1 AND E2.canceled_status='no' AND E2.region_id=2 GROUP BY region_id) a1 ON a1.region_id=E.region_id
LEFT OUTER JOIN (SELECT E2.region_id, count(`id`) AS status0
FROM tbl_insurance_excel E2 LEFT JOIN tbl_recipt_general_details ON id=insurance_excel_id
JOIN tbl_branches ON policy_closed_branch= branch_id
WHERE E2.`row_status` =0 AND E2.canceled_status='no' AND E2.region_id=2 GROUP BY region_id) a0 ON a0.region_id=E.region_id
LEFT JOIN (
SELECT IEX.region_id, B.branch_name AS branch_names, B.branch_id AS branches, sum( DDT.discounts_amount ) AS discount, sum( RGD.`recipt_bal_amount` ) AS balance
FROM tbl_insurance_excel IEX
LEFT JOIN tbl_recipt_general_details RGD ON IEX.id = RGD.insurance_excel_id
LEFT JOIN tbl_discounts_details DDT ON RGD.rec_gene_id = DDT.recipt_general_id
LEFT JOIN tbl_branches B ON B.branch_id = RGD.policy_closed_branch
WHERE IEX.region_id =2
GROUP BY B.branch_id)k ON k.region_id=E.region_id
LEFT JOIN (
SELECT ex.region_id, B.branch_id AS branches, count( F.`fse_id` ) AS telecallers
FROM tbl_branches B
LEFT JOIN tbl_team_leader L ON B.branch_id = L.leader_branch_id
LEFT JOIN tbl_fse F ON L.leader_id = F.leader_id
JOIN (
SELECT region_id
FROM tbl_insurance_excel
WHERE `region_id` =2
GROUP BY region_id
) AS ex ON B.region_id = ex.region_id
WHERE F.fse_category = 'Telecaller'
GROUP BY B.branch_id
) TCLRS ON TCLRS .region_id=E.region_id
LEFT JOIN (
SELECT ex.region_id, B.branch_id AS branches, count( F.`fse_id` ) AS fses
FROM tbl_branches B
LEFT JOIN tbl_team_leader L ON B.branch_id = L.leader_branch_id
LEFT JOIN tbl_fse F ON L.leader_id = F.leader_id
JOIN (
SELECT region_id
FROM tbl_insurance_excel
WHERE `region_id` =2
GROUP BY region_id
) AS ex ON B.region_id = ex.region_id
WHERE F.fse_category = 'Fse'
GROUP BY B.branch_id
) FSE ON FSE.region_id=E.region_id
WHERE E.region_id=2 GROUP BY k.branches
请注意，您正在一个接一个地进行连接，并组合查询中应该唯一的结果。您已将来自您命名为 k 的查询的数据连接起来，然后将结果与您命名为 BAL 的查询连接起来，除了 balance 列之外，具有相同的条目，因此 branch_id's被复制了。
你有，很快：
k.branch_id LEFT JOIN BAL.branch_id
这导致您的行被重复，具有不同的balance 值。
发布的查询得到的结果是：
REGION_ID STATUS0 STATUS1 DISCOUNT BRANCHES BRANCH_NAMES BALANCE TELECALLERS FSES
2 (null) 4 400 30 KOTTAKKAL 341 3 3
2 (null) 4 800 31 KALPETTA 394 3 3
问候！