【发布时间】:2014-11-09 20:48:41
【问题描述】:
我有 2 张桌子 - departments 和 employees。我想从departments 中选择所有列,并添加一个列,其中包含子部门数和每个部门的员工数。
简化后的表格如下所示:
departments:
id name parent_id
---------------------------------
1 IT NULL
2 HR NULL
3 Bussiness NULL
4 Web dev 1
5 Ecommerce 4
6 Advertisement 3
7 Control 3
8 Programmers 1
employees:
id name department_id
---------------------------------
1 Adam 1
2 Ben 8
3 Charles 7
4 David 4
5 Eugen 4
6 Frank 6
7 Gustav 6
8 Heremy 4
9 Igor 5
10 Jacob 3
我想要的结果是:
id name parent_id department_count employee_count
----------------------------------------------------------------------------
1 IT NULL 2 1
2 HR NULL 0 0
3 Bussiness NULL 2 1
4 Web dev 1 1 3
5 Ecommerce 4 0 1
6 Advertisement 3 0 2
7 Control 3 0 1
8 Programmers 1 0 1
这是我的查询,但它不能正常工作。但是,如果我删除了COUNT 中的 1 个,则数字是正确的。我认为NULL 值是问题所在,但我不知道解决方案。
SELECT d.*, COUNT(d2.parent_id) AS department_count, COUNT(e.id) AS employee_count
FROM department AS d
LEFT JOIN department AS d2 ON (d.id = d2.parent_id)
LEFT JOIN employees AS z ON (e.department_id = d.id)
GROUP BY d.id
ORDER BY d.id
欢迎对我的代码进行任何改进。
【问题讨论】:
-
对不起,我的错 - 应该是 2