TSQL：使用不同的列对记录进行排名

Question

我有一张表格，上面有人员及其费用以及其他一些列。我需要的是创建两个新列：ranking1 和ranking2。这些排名是通过使用一些列和聚合来“计算”的。

ranking1: if total of person expenses exceeds 1000 then ranking 1 else ranking 0
ranking2: (if Col1 = 1 then 0 else 5) + (if Col2 = 1 then 0 else 7) + (if Col3 = 1 then 5 else 10)

我需要的是原始表（未更改），其中包含这两个新列，可以为我提供每个人的排名。

我的查询：

select Col1, Col2, Col3
       ((CASE Col1 = 1 THEN 0 ELSE 5 END) + 
        (CASE WHEN Col2 = 1 THEN 0 ELSE 7 END) + 
        (CASE WHEN Col3 = 1 THEN 5 WHEN Col3 = 2 THEN 2 ELSE 10 END)) as ranking, tmp.Expenses    from table t
left join (select id, Person, 
          (case when temp.expenses > 1000 then 1 else 0 end) as UserExpenses 
           from (select id, Person, sum(Expenses) as expenses 
           from table 
           group by id, Person) temp) tmp
on t.Person = tmp.Person and t.id = tmp.id
order by ranking desc, tmp.UserExpenses desc

我怀疑这个查询是否会给我我想要的东西，即带有两个新列作为排名的原始未更改表。特别是我对左连接持怀疑态度，它是右连接吗？提前致谢

Answer 1

您的查询应该会给您带来正确的结果。以下是您的查询的简化版本：

select  Col1,
        Col2, 
        Col3
        (CASE WHEN Col1 = 1 THEN 0 ELSE 5 END) + 
        (CASE WHEN Col2 = 1 THEN 0 ELSE 7 END) + 
        (CASE WHEN Col3 = 1 THEN 5 WHEN Col3 = 2 THEN 2 ELSE 10 END) as ranking, 
        (case when temp.expenses > 1000 then 1 else 0 end) as Expenses    
from [table] t
OUTER APPLY (select id, 
                    Person, 
                    sum(Expenses) as expenses 
            from [table] 
            where t.Person = Person and t.id = id
            group by id, Person
            ) temp
order by ranking desc, temp.expenses desc