如何在使用 mysql 的 select 中使用内部连接？答案

【问题标题】：How to use inner join in select with mysql?如何在使用 mysql 的 select 中使用内部连接？
【发布时间】：2012-12-13 14:15:33
【问题描述】：

我想在以下条件下从 mysql 数据库中获取记录

我有以下表格：

组织_表
```
organizationId | organizationname
```

活动表

camp_id | camp_name | adv_id | organizationId

广告表
```
adv_id | adv_name
```
ad_display 表
```
ad_displayId | adv_id | camp_id |
```

现在我想从 ad_display 表中获取这样的记录：

| adv_name | camp_name | organizationname

将WHERE Condtion 设为 Where organizationId == ?

所以基本上我想要organization_id=?的广告系列的广告列表？

注意：同一个 adv_id 在 camapign 表中应该有多个条目，并且同一个 camp_id 在 ad_display 中应该有多个条目

【问题讨论】：

标签： mysql sql select join

【解决方案1】：

试试这个：

SELECT ad.ad_displayId, a.adv_name, c.camp_name, o.organizationname 
FROM ad_display ad 
INNER JOIN advertise a ON ad.adv_id = a.adv_id 
INNER JOIN campaign c ON ad.camp_id = c.camp_id 
INNER JOIN organization o ON c.organizationId = o.organizationId 
WHERE o.organizationId = ?;

【讨论】：

thnx ...它的工作..实际上是这个 mysql 和 sql 查询的新手......但是你们所有人都很快..tnx

【解决方案2】：

也许是这样的？

SELECT Distinct
  advertise.adv_name,
  campaign.camp_name,
  organization_.organizationname
FROM
  advertise inner join campaign
  on advertise.adv_id = campaign.adv_id
  inner join organization_
  on campaign.organizationID = organization_.organizationID
WHERE
  organization_.organizationID = 1

【讨论】：

【解决方案3】：

SELECT  advertise.adv_name, 
        campaign.camp_name, 
        organization_Table.organizationname
FROM   ad_display 
    INNER JOIN advertise ON ad_display.adv_id = advertise.adv_id 
    INNER JOIN campaign ON ad_display.camp_id = campaign.camp_id 
    INNER JOIN organization_ Table ON campaign.organizationId = organization_Table.organizationId
    AND organization_Table.organizationId=?

【讨论】：

【解决方案4】：

SELECT * FROM campaign
LEFT JOIN ad_display ON campaign.camp_id = ad_display.camp_id
LEFT JOIN advertise ON ad_display.adv_id = advertise.adv_id
WHERE campaign.organizationId = <?>

【讨论】：

【解决方案5】：

使用下面的代码

SELECT dv_name,
       camp_name,
       organizationname
FROM   organization
       inner join campaign
               ON organization.organizationid == campaign.organizationid
       left join advertise
              ON campaign.adv_id == advertise.adv_id
WHERE  condition =? ;

【讨论】：

【解决方案6】：

SELECT batch_number,
       Count(receipt_number) AS tot_rec,
       Sum(amount)           AS tot_amount
FROM   receipt_header
GROUP  BY batch_number
UNION ALL
SELECT batch_number,
       Count(receipt_lines.receipt_number),
       Sum(receipt_lines.amount)
FROM   receipt_lines
       INNER JOIN receipt_header
               ON receipt_header.record_id = receipt_lines.header_record_id
GROUP  BY batch_number
ORDER  BY batch_number ASC;

【讨论】：