如何将两个完全不同的 SQL 查询组合成一个结果答案

【问题标题】：How to combine two completely different SQL queries into one result如何将两个完全不同的 SQL 查询组合成一个结果
【发布时间】：2019-01-09 03:38:36
【问题描述】：

我对 SQL 查询很陌生，需要一些帮助。

我有两个不同的 SQL 查询，我希望将两者的结果放在一个结果中。

查询 1：

SELECT 
    gbkmut.bkstnr_sub, 
    MAX(orkrg.refer) AS oms25, 
    MAX(gbkmut.docnumber) AS YourRef, 
    MIN(gbkmut.datum) AS datum, 
    cicmpy.debcode AS delv_debnr, 
    MAX(cicmpy.cmp_name) AS cmp_name,
    MAX(gbkmut.datum) AS latest_deldat, 
FROM 
    gbkmut 
INNER JOIN 
    orkrg ON gbkmut.bkstnr_sub = orkrg.ordernr
INNER JOIN
    cicmpy ON orkrg.verzdebnr  = cicmpy.debnr
INNER JOIN 
    items ON gbkmut.artcode = items.itemcode AND items.type <> 'P'
INNER JOIN 
    magaz ON gbkmut.warehouse = magaz.magcode AND magaz.blokkeer = 0 
WHERE 
    (gbkmut.transsubtype IN ('B','H')
     AND gbkmut.freefield1 = 'V'
     AND gbkmut.Blockitem = 0
     AND gbkmut.afldat <= GETDATE()) 
    AND gbkmut.Checked = 1 
    AND (orkrg.ordbv_afdr = 0 OR (orkrg.ordbv_afdr = 1 AND orkrg.ordbv_afgd = 1)) 
GROUP BY 
    gbkmut.bkstnr_sub, 
    gbkmut.afldat, 
    cicmpy.debcode
ORDER BY 
    gbkmut.bkstnr_sub DESC

查询 2：

SELECT TOP 1000 
    [Debtor code],
    [Outstanding Amount]
FROM 
    [456].[dbo].[GRV_DebtorOutstanding]

[债务人代码] 和 cicmpy.debcode 对于连接是相同的

两个查询的一些示例结果：

查询 1 列：

Ordernumber, Order description, Your reference, Orderdate, Debtor code, Debtor name, Order delivery date

   20093    NULL    Bestel.: 20093  2018-07-31 00:00:00.000                60089    Restaurant Enkhuizen    2018-07-31 00:00:00.000
   20092    NULL    Bestel.: 20092  2018-07-31 00:00:00.000                60089    Restaurant Enkhuizen    2018-07-31 00:00:00.000
   20088    NULL    Bestel.: 20088  2018-07-05 00:00:00.000                60105    Brasserie Pigalle   2018-07-05 00:00:00.000

查询 2：

列：债务人代码、未偿还总额

Debtor code Outstanding Amount
               60086    -30,65
               60092    -121
               60089    -5000
               60130    1000

我想将未结清总额添加到第一个查询中。

我尝试使用子选择，但出现错误：

子查询返回超过 1 个值。当子查询跟随 =、!=、、>= 或子查询用作表达式时，这是不允许的。

由于不同的列，联合也可能是不可能的。

我想将其用于报告目的，当然可以通过 Excel 和 vlookup 解决它，但我想在 SQL 中完成它以了解有关 SQL 的更多信息。

任何帮助都会很棒。谢谢

【问题讨论】：

如果您可以使用VLOOKUP，那么您可以将结果放入临时表并最有可能进行左连接：docs.microsoft.com/en-us/sql/t-sql/statements/…
请发布使用子查询的尝试，以便我们告诉您为什么遇到错误。
您可以将第二个查询设为子查询，然后加入它——这两个查询如何加入呢？你怎么知道 1 中的哪一行要从 2 中添加债务？
也许这就是你要找的东西：stackoverflow.com/questions/11574442/…

标签： sql sql-server

【解决方案1】：

将它们放在子查询中并将它们连接在一起

SELECT * FROM
(
SELECT 
    gbkmut.bkstnr_sub, 
    MAX(orkrg.refer) AS oms25, 
    MAX(gbkmut.docnumber) AS YourRef, 
    MIN(gbkmut.datum) AS datum, 
    cicmpy.debcode AS delv_debnr, 
    MAX(cicmpy.cmp_name) AS cmp_name,
    MAX(gbkmut.datum) AS latest_deldat, 
FROM 
    gbkmut 
INNER JOIN 
    orkrg ON gbkmut.bkstnr_sub = orkrg.ordernr
INNER JOIN
    cicmpy ON orkrg.verzdebnr  = cicmpy.debnr
INNER JOIN 
    items ON gbkmut.artcode = items.itemcode AND items.type <> 'P'
INNER JOIN 
    magaz ON gbkmut.warehouse = magaz.magcode AND magaz.blokkeer = 0 
WHERE 
    (gbkmut.transsubtype IN ('B','H')
     AND gbkmut.freefield1 = 'V'
     AND gbkmut.Blockitem = 0
     AND gbkmut.afldat <= GETDATE()) 
    AND gbkmut.Checked = 1 
    AND (orkrg.ordbv_afdr = 0 OR (orkrg.ordbv_afdr = 1 AND orkrg.ordbv_afgd = 1)) 
GROUP BY 
    gbkmut.bkstnr_sub, 
    gbkmut.afldat, 
    cicmpy.debcode
ORDER BY 
    gbkmut.bkstnr_sub DESC
) T1
JOIN 
(
    SELECT TOP 1000 
        [Debtor code],
        [Outstanding Amount]
    FROM 
        [456].[dbo].[GRV_DebtorOutstanding]
) T2 ON T2.[Debtor code] = T1.delv_debnr

【讨论】：

【解决方案2】：

    Select * from (


    SELECT 
    gbkmut.bkstnr_sub, 
    MAX(orkrg.refer) AS oms25, 
    MAX(gbkmut.docnumber) AS YourRef, 
    MIN(gbkmut.datum) AS datum, 
    cicmpy.debcode AS delv_debnr, 
    MAX(cicmpy.cmp_name) AS cmp_name,
    MAX(gbkmut.datum) AS latest_deldat, 
FROM 
    gbkmut 
INNER JOIN 
    orkrg ON gbkmut.bkstnr_sub = orkrg.ordernr
INNER JOIN
    cicmpy ON orkrg.verzdebnr  = cicmpy.debnr
INNER JOIN 
    items ON gbkmut.artcode = items.itemcode AND items.type <> 'P'
INNER JOIN 
    magaz ON gbkmut.warehouse = magaz.magcode AND magaz.blokkeer = 0 
WHERE 
    (gbkmut.transsubtype IN ('B','H')
     AND gbkmut.freefield1 = 'V'
     AND gbkmut.Blockitem = 0
     AND gbkmut.afldat <= GETDATE()) 
    AND gbkmut.Checked = 1 
    AND (orkrg.ordbv_afdr = 0 OR (orkrg.ordbv_afdr = 1 AND orkrg.ordbv_afgd = 1)) 
GROUP BY 
    gbkmut.bkstnr_sub, 
    gbkmut.afldat, 
    cicmpy.debcode


    Union all

    SELECT TOP 1000 
    bkstnr_sub as '',
    oms25 as 0,
    YourRef as 0, 
    datum as 0,
    delv_debnr as 0, 
    cmp_name as ''
    [Debtor code],
    latest_deldat as NULL
    [Outstanding Amount]
FROM 
    [456].[dbo].[GRV_DebtorOutstanding]
 ) as outertable

【讨论】：

您可以通过与第一个查询相同的列别名来完成。我已将其放入子选择中，因此您也可以使用外部选择进行其他操作。

【解决方案3】：

您可以通过将第二个查询设为公用表表达式来做到这一点：

WITH agg
AS (SELECT TOP 1000
           [Debtor code]
         , [Outstanding Amount]
    FROM [456].[dbo].[GRV_DebtorOutstanding])
SELECT gbkmut.bkstnr_sub
     , MAX(orkrg.refer) AS oms25
     , MAX(gbkmut.docnumber) AS YourRef
     , MIN(gbkmut.datum) AS datum
     , cicmpy.debcode AS delv_debnr
     , MAX(cicmpy.cmp_name) AS cmp_name
     , MAX(gbkmut.datum) AS latest_deldat
     , ISNULL(agg.[Outstanding Amount],0) AS [Outstanding Amount]
FROM gbkmut
    INNER JOIN orkrg ON gbkmut.bkstnr_sub = orkrg.ordernr
    INNER JOIN cicmpy ON orkrg.verzdebnr = cicmpy.debnr
    INNER JOIN items ON gbkmut.artcode = items.itemcode
                        AND items.type <> 'P'
    INNER JOIN magaz ON gbkmut.warehouse = magaz.magcode
                        AND magaz.blokkeer = 0
    LEFT OUTER JOIN agg ON agg.[Debtor code] = cicmpy.debcode
WHERE (
          gbkmut.transsubtype IN ( 'B', 'H' )
          AND gbkmut.freefield1 = 'V'
          AND gbkmut.Blockitem = 0
          AND gbkmut.afldat <= GETDATE()
      )
      AND gbkmut.Checked = 1
      AND
      (
          orkrg.ordbv_afdr = 0
          OR
          (
              orkrg.ordbv_afdr = 1
              AND orkrg.ordbv_afgd = 1
          )
      )
GROUP BY gbkmut.bkstnr_sub
       , gbkmut.afldat
       , cicmpy.debcode
       , agg.[Outstanding Amount]
ORDER BY gbkmut.bkstnr_sub DESC;

【讨论】：