【发布时间】:2019-06-06 15:38:33
【问题描述】:
为什么 pylint 在函数外部接受大写变量而在函数内部拒绝它们?相反,为什么 pylint 在函数外拒绝 camelCase 并在函数内接受它?
我刚刚安装了 pylint(版本 2.2.2)来检查我的 Python 3。一定有什么我错过了。我的相关 Python/包版本是:
pylint 2.2.2
astroid 2.1.0
Python 3.6.7 | packaged by conda-forge | (default, Nov 20 2018, 18:20:05)
[GCC 4.2.1 Compatible Apple LLVM 9.0.0 (clang-900.0.37)]
考虑以下代码 (test_1),其中我使用 camelCase 和 Capitalized 命名变量。 Capitalized 变量被接受(为什么?)并且 camelCase 被拒绝(因为代码没有被包装到函数中,我猜)。
'''
Nothing important
'''
fileHandler = open("afile.txt")
for line in fileHandler:
Token = line.split("\t")
Part_1 = Token[0]
print(Part_1)
在调用 pylint 时给出:
$ pylint --py3k --enable=all test_1.py
************* Module test_1
test_1.py:5:0: C0103: Constant name "fileHandler" doesn't conform to UPPER_CASE naming style (invalid-name)
------------------------------------------------------------------
Your code has been rated at 8.00/10 (previous run: 8.00/10, +0.00)
现在,如果我将所有内容都放入一个函数 (test_2)。
'''
Nothing important
'''
def foo():
fileHandler = open("afile.txt")
for line in fileHandler:
Token = line.split("\t")
Part_1 = Token[0]
print(Part_1)
if __name__ == '__main__':
foo()
然后大写的变量被检测为不合规(这是我的预期):
$ pylint --py3k --enable=all test_2.py
************* Module test_2
test_2.py:5:0: C0102: Black listed name "foo" (blacklisted-name)
test_2.py:5:0: C0111: Missing function docstring (missing-docstring)
test_2.py:6:4: C0103: Variable name "fileHandler" doesn't conform to snake_case naming style (invalid-name)
test_2.py:9:8: C0103: Variable name "Token" doesn't conform to snake_case naming style (invalid-name)
test_2.py:10:8: C0103: Variable name "Part_1" doesn't conform to snake_case naming style (invalid-name)
------------------------------------------------------------------
Your code has been rated at 3.75/10 (previous run: 3.75/10, +0.00)
我有一些不清楚的地方...欢迎任何澄清...
最好的
【问题讨论】:
标签: python pylint capitalize