如何迭代由json对象中的键访问的数组[重复]答案

【问题标题】：How can I iterate over an array that is accesed by a key in a json Object [duplicate]如何迭代由json对象中的键访问的数组[重复]
【发布时间】：2016-05-03 03:32:14
【问题描述】：

这是我的字符串化 JSON 对象：

{
    "bookingsList": [{
        "bookingID": 5,
        "destination": "BSO",
        "flightDate": "2015-12-07T00:00:00",
        "flightScheduleId": 113,
        "origin": "MNL",
        "passengerList": [{
            "availedInsurance": true,
            "availedMeal": false,
            "birthDate": null,
            "carryOnBaggage": 5.1,
            "checkInBaggage": 4.5,
            "columnId": 1,
            "firstname": "Peter",
            "gender": "M",
            "lastname": "North",
            "middlename": "West",
            "nationality": null,
            "rowId": "A"
        }]
    }, {
        "bookingID": 6,
        "destination": "BSO",
        "flightDate": "2015-12-07T00:00:00",
        "flightScheduleId": 113,
        "origin": "MNL",
        "passengerList": [{
            "availedInsurance": false,
            "availedMeal": false,
            "birthDate": null,
            "carryOnBaggage": 4.2,
            "checkInBaggage": 3.4,
            "columnId": 2,
            "firstname": "Mark Justin",
            "gender": "M",
            "lastname": "Jalandoni",
            "middlename": "Manzano",
            "nationality": null,
            "rowId": "A"
        }]
    }]
}

那么我该如何迭代 bookingsList 中的对象呢？我将在桌子上放置一些属性。

编辑：原来我使用的 for in 循环没有迭代，因为我忘记在可迭代对象变量之前放置一个“var”。

【问题讨论】：

bookingsList 只是一个数组，所以任何循环结构都可以，例如一个普通的旧 for 循环。
你知道循环的概念吗？？？

标签： jquery json

【解决方案1】：

一个简单的for循环就足够了：

var jsonObj = {
    "bookingsList": [{
        "bookingID": 5,
        "destination": "BSO",
        "flightDate": "2015-12-07T00:00:00",
        "flightScheduleId": 113,
        "origin": "MNL",
        "passengerList": [{
            "availedInsurance": true,
            "availedMeal": false,
            "birthDate": null,
            "carryOnBaggage": 5.1,
            "checkInBaggage": 4.5,
            "columnId": 1,
            "firstname": "Peter",
            "gender": "M",
            "lastname": "North",
            "middlename": "West",
            "nationality": null,
            "rowId": "A"
        }]
    }, {
        "bookingID": 6,
        "destination": "BSO",
        "flightDate": "2015-12-07T00:00:00",
        "flightScheduleId": 113,
        "origin": "MNL",
        "passengerList": [{
            "availedInsurance": false,
            "availedMeal": false,
            "birthDate": null,
            "carryOnBaggage": 4.2,
            "checkInBaggage": 3.4,
            "columnId": 2,
            "firstname": "Mark Justin",
            "gender": "M",
            "lastname": "Jalandoni",
            "middlename": "Manzano",
            "nationality": null,
            "rowId": "A"
        }]
    }]
}

// For easy reference
var bookingsList = jsonObj.bookingsList;

for (i = 0; i < bookingsList.length; i++) {
    var booking = bookingsList[i]; // Grab booking data
    console.log(booking.bookingID); // Log booking data
}

【讨论】：

【解决方案2】：

$.each(json.bookingsList, function(index, prop){
     console.log(prop);
});

【讨论】：

纯代码答案对于帮助 OP 了解正在发生的事情并没有真正有用。也许给你的答案一个简短的解释。